In one revolution of the wheel, a point on the edge travels a distance equal to the circumference of the wheel.
The wheel has radius 1 ft, so its circumference is 2π (1 ft) = 2π ft.
Then the point has a linear speed of
(1/4 rev/s) * (2π ft/rev) = 2π/4 ft/s = π/2 ft/s
Answer:
RS = 75.3
Step-by-step explanation:
You need to set up the proportion of corresponding sides.


7(RS) = 31(17)
= 527
RS = 527/7 = 75.2857...
= 75.3
Answer:
20 kilograms
Step-by-step explanation: