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2 years ago

Henry is following the recipe card to make a

Mathematics

2 answers:

omeli [17]2 years ago

6 0

Answer:

Step-by-step explanation:

Feliz [49]2 years ago

5 0

You divide the number of flour by the number of recipe card

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PLEASE HELP!!!! The problem is in the photo below.

Sergio039 [100]

Answer:

A is correct.

Step-by-step explanation:

Here, the x would represent the gallons per minute. The minutes are unknown, so it's just a variable. It can't be B either, because the addition sign would mean that the pool is being filled instead of drained.

8 0

2 years ago

Solve:

Delvig [45]

Answer:

D. x=12/11 or x=32/11.

4 0

2 years ago

Read 2 more answers

Write 1/10^2 using exponents

Viefleur [7K]

Answer:

I think it would be 100

Step-by-step explanation:

because 10^2 is 10 x 10 which equals 100 and so if you have 1/10^2 it's basically saying 1 divided by 10^2 and 10^2 is 100 so it would be 1 divided by 100 which equals 100.

I hope this helped any.

4 0

3 years ago

Paul has $40000 to invest. His intent is to earn 9% interest on his investment. He can invest part of his money at 6% and part a

Black_prince [1.1K]

Paul needs to invest $10000 at 6% interest and $30000 at 10% interest to make a total of 9% return on his $40000.

Explanation

Suppose, the amount of money at 6% interest is $x$

As Paul has total $40000 to invest, so the amount of money at 10% interest will be: $(40000-x) dollar$

His intent is to earn 9% interest on his $40000 investment. So, the equation will be......

$0.06x+0.10(40000-x)=0.09*40000\\ \\ 0.06x+4000-0.10x=3600\\ \\ -0.04x=3600-4000=-400\\ \\ x=\frac{-400}{-0.04}=10000$

So, Paul needs to invest $10000 at 6% interest and ($40000- $10000) or $30000 at 10% interest to make a total of 9% return on his $40000.

3 0

2 years ago

Read 2 more answers

Let f be defined by the function f(x) = 1/(x^2+9)

riadik2000 [5.3K]

(a)

$\displaystyle\int_3^\infty \frac{\mathrm dx}{x^2+9}=\lim_{b\to\infty}\int_{x=3}^{x=b}\frac{\mathrm dx}{x^2+9}$

Substitute x = 3 tan(t ) and dx = 3 sec²(t ) dt :

$\displaystyle\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\frac{3\sec^2(t)}{(3\tan(t))^2+9}\,\mathrm dt=\frac13\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\mathrm dt$

$=\displaystyle \frac13 \lim_{b\to\infty}\left(\arctan\left(\frac b3\right)-\arctan(1)\right)=\boxed{\dfrac\pi{12}}$

(b) The series

$\displaystyle \sum_{n=3}^\infty \frac1{n^2+9}$

converges by comparison to the convergent p-series,

$\displaystyle\sum_{n=3}^\infty\frac1{n^2}$

$\displaystyle \sum_{n=1}^\infty \frac{(-1)^n (n^2+9)}{e^n}$

converges absolutely, since

$\displaystyle \sum_{n=1}^\infty \left|\frac{(-1)^n (n^2+9)}{e^n}\right|=\sum_{n=1}^\infty \frac{n^2+9}{e^n} < \sum_{n=1}^\infty \frac{n^2}{e^n} < \sum_{n=1}^\infty \frac1{e^n}=\frac1{e-1}$

That is, ∑ (-1)ⁿ (n ² + 9)/eⁿ converges absolutely because ∑ |(-1)ⁿ (n ² + 9)/eⁿ| = ∑ (n ² + 9)/eⁿ in turn converges by comparison to a geometric series.

5 0

2 years ago