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blsea [12.9K]
3 years ago
8

Which values of PP and QQ result in an equation with no solutions? -60x+32=Qx+P−60x+32=Qx+P Choose all answers that apply: Choos

e all answers that apply: (Choice A) A Q=-60Q=−60 and P=60P=60 (Choice B) B Q=32Q=32 and P=60P=60 (Choice C) C Q=-60Q=−60 and P=-32P=−32 (Choice D) D Q=32Q=32 and P=-60P=−60
Mathematics
1 answer:
Inga [223]3 years ago
8 0
<h3>Answer:</h3>

  A and C

<h3>Step-by-step explanation:</h3>

Given:

  -60x+32 = Qx+P

Find:

Which values of P and Q result in an equation with no solutions? Choose all answers that apply:

(Choice A) A Q=-60 P=60

(Choice B) B Q=32 P=60

(Choice C) C Q=-60 P=−32

(Choice D) D Q=32 P=−60

Solution:

The equation will have no solution if it reduces to ...

  0 = (non-zero constant)

If we add 60x-32 to both sides, we get

  0 = 60x +Qx + P-32

  0 = (Q+60)x +(P-32)

The x-term must be zero, so Q+60 = 0, or Q = -60.

The constant term must be non-zero, so P-32 ≠0, or P ≠ 32.

The appropriate answer choices are those with Q=-60 and P≠32, A and C.

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What’s the area of a rectangle measuring 13 inches times 12 inches ?
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Answer:

156 square inches

Step-by-step explanation:

We are given the two quantities

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Putting the values of both that are given

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6 0
3 years ago
These box plots show the basketball scores for two teams.
Arisa [49]

The most appropriate statement is the interquartile range for the Wolverines, 30 is less than the IQR for the panthers, 40.

<h3>What is the correct statement?</h3>

The box plot is used to show the distribution of data. The box plot can be used to determine the range, interquartile range and median of the data set.

The range is the difference between the two ends of the whiskers.

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The interquartile range is the difference between the first and third lines on the box

IQR for the Wolverines = 85 - 55 = 30

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6 0
2 years ago
A new park was designed to contain two circular gardens. Garden A had a diameter 50 m, anf garden B has a diameter of 70 m. If t
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3 years ago
PLEASE HELP!!!! Show steps and explain how to get the answer please <br><br> Solve 5x-16=4(x-8)-3x
Anvisha [2.4K]

5x-16 = 4(x-8)-3x

first expand what is in parenthesis

4(x-8) = 4x-32

 so now you have 5x-16 = 4x-32-3x

subtract 3x from 4x on the right side of equation 4x-3x = x

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subtract 1x from each side to get

4x-16 = -32

add 16 to both sides to get 4x=-16

x = -16/4 = -4

x=-4

6 0
3 years ago
Read 2 more answers
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