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bija089 [108]
3 years ago
7

Higgins Middle School hosted a mathematics competition. The algebraic proof

Mathematics
1 answer:
motikmotik3 years ago
7 0

Commutative Property of Addition

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Function help please
Korvikt [17]

Answer:

The first table represents a function.

Step-by-step explanation:

For it to be a function, there needs to be 1 unique y value of 1 unique x value.

  • Looking at 2nd table, we see x value of -5 is mapped to 2 different y values of -5 and 5. So this is not a function.
  • Looking at 3rd table, we see x value of -2 is mapped to 2 different y values of 2 and 4. So this is not a function.
  • Looking at 4th table, we see x value of -4 is mapped to 2 different y values of 2 and 0. So this is not a function as well.

Looking at table 1, there are no duplicate x values and each of the 4 x values map to different values. So the first table represents a function.

4 0
3 years ago
1/3k+80=1/2k+120 what does k equal?
LenaWriter [7]

Answer:

k = -1/240

Step-by-step explanation:

to evaluate the value of k in the expression 1/3k+80=1/2k+120

we have

1/3k+80=1/2k+120

collect the like terms for easy evaluation

1/3k - 1/2k = 120 -80

1/3k - 1/2k = 40

find the lcm

2 - 3/6k = 40

-1/ 6k = 40

cross multiply

6k  x  40  = -1

240k = -1

divide both sides by 240

240k/240 = -1/ 240

k = -1/240

therefore the value of k in the expression 1/3k+80=1/2k+120 is equals to -1/240

8 0
2 years ago
Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. ​(a) Descri
OlgaM077 [116]

Part a)

The simple random sample of size n=36 is obtained from a population with

\mu = 74

and

\sigma = 6

The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

\mu = 74

The standard error of the means becomes the standard deviation of the sampling distribution.

\sigma_ { \bar X }  =  \frac{ \sigma}{ \sqrt{n} }  \\ \sigma_ { \bar X }  =  \frac{ 6}{ \sqrt{36} }  = 1

Part b) We want to find

P(\bar X \:>\:75.9)

We need to convert to z-score.

P(\bar X \:>\:75.9)  = P(z \:>\: \frac{75.9 - 74}{1} )  \\  = P(z \:>\: \frac{75.9 - 74}{1} ) \\  = P(z \:>\: 1.9) \\  = 0.0287

Part c)

We want to find

P(\bar X \: < \:71.95)

We convert to z-score and use the normal distribution table to find the corresponding area.

P(\bar X \: < \:71.95)  = P(z \: < \: \frac{71.9 5- 74}{1} )  \\  = P(z \: < \: \frac{71.9 5- 74}{1} ) \\  = P(z \: < \:  - 2.05) \\  = 0.0202

Part d)

We want to find :

P(73\:

We convert to z-scores and again use the standard normal distribution table.

P( \frac{73 - 74}{1} \:< \: z

5 0
3 years ago
(17-7)•6+2+56-8<br> Pemdas
givi [52]
I don’t even know the answer to be honest
4 0
3 years ago
Read 2 more answers
Answer the question please:<br> The correct answer will be marked as brainliest =)<br> thanks xoxo
Nataly [62]
100,000,000 is the answer
4 0
2 years ago
Read 2 more answers
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