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3 years ago

Tens and ones combinations. 30 + ? + ? + ? / ? + ? = 92

Mathematics

2 answers:

BlackZzzverrR [31]3 years ago

6 0

The answer is 90 I hope it helps you

BlackZzzverrR [31]3 years ago

3 0

i know the answer its 90

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If per unit variable cost of a product is Rs.8 and fixed cost is Rs 5000 and it is sold for Rs 15 per unit, profit in 1000 units

ExtremeBDS [4]

Answer:

a.. rs 7000

Because 15×1000=15000 it is SP when selling 1000units in the rate of Rs 15/unit& 8×1000=8000 this is cp when buying 1000 units in the rate of Rs 8/unit.

So,by formula of profit,

Rs (15000-8000)=Rs7000

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3 years ago

100 POINTS HURRY

Travka [436]

Answer :

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4 years ago

What is the product?

fredd [130]

Answer:

$\frac{4k + 2}{k^{2}-4 }$ × $\frac{k-2}{2k+1}$ = $\frac{2}{k + 2}$

Step-by-step explanation:

$\frac{4k + 2}{k^{2}-4 }$ × $\frac{k-2}{2k+1}$

To solve the above, we need to follow the steps below;

4k+2 can be factorize, so that;

4k +2 = 2 (2k + 1)

k² - 4 can also be be expanded, so that;

k² - 4 = (k-2)(k+2)

Lets replace 4k +2 by 2 (2k + 1)

and

k² - 4 by (k-2)(k+2) in the expression given

$\frac{4k + 2}{k^{2}-4 }$ × $\frac{k-2}{2k+1}$

$\frac{2(2k+ 1)}{(k-2)(k+2)}$ × $\frac{k-2}{2k+1}$

(2k+1) at the numerator will cancel-out (2k+1) at the denominator, also (k-2) at the numerator will cancel-out (k-2) at the denominator,

So our expression becomes;

$\frac{2}{k + 2}$

Therefore, $\frac{4k + 2}{k^{2}-4 }$ × $\frac{k-2}{2k+1}$ = $\frac{2}{k + 2}$

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4 years ago

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Suppose your school is having a talent show to raise money for new band supplies. You think that 200 students and 150 adults wil

Liono4ka [1.6K]

800= 150x+200y

hope this helps :)

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3 years ago

SOMEONE PLEASE I NEED HELP Find a polynomial f(x) of degree 4 that has the following zeros. 6, 5, -4, -7 - Leave your answer in

sattari [20]

Answer:

$y=(x-6)(x-5)(x+4)(x+7)$

Step-by-step explanation:

Formulate the equation of the polynomial function

$y=(x-6)(x-5)(x+4)(x+7)$

I hope this helps you

:)

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3 years ago

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