Find the area of square ABCD in whichdiagonal BD=3√2cm
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the coordinates of the points of intersection of the graph of y=13−x with the axes
Given equation is y=13-x
x axis is x=0
y axis is y=0
Plug in the value of x =0 and find out y
y = 13 - x
y = 13 - 0 = 13
Plug in the value of y=0 and find out x
0 = 13 - x
x= 13
So coordinate axis
x= (13,0)
y= (0,13)
Base of the triangle is x=13
Height of the triangle is y= 13
Area of the triangle =
= = 84.5
Area of the triangle = 84.5