Find the area of square ABCD in whichdiagonal BD=3√2cm
1 answer:
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Answer:
here you go
Step-by-step explanation:
Answer:
Part 1)
Bob's mistake was to have used the cosine instead of the sine
The measure of the missing angle is
Part 2) The surface area of the pyramid is
Step-by-step explanation:
Part 1)
Let
x----> the missing angle
we know that
In the right triangle o the figure
The sine of angle x is equal to divide the opposite side angle x to the hypotenuse of the right triangle
Bob's mistake was to have used the cosine instead of the sine
Part 2) we know that
The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces
so
where
b is the length side of the square
h is the height of the triangular lateral face
In this problem
-------> by an 45° angle
so
Find the value of b
Find the surface area