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3 years ago

HELPPP PLEASEEE!!!!!!!

Mathematics

1 answer:

Vladimir79 [104]3 years ago

6 0

Answer:

CFX, ADC

Step-by-step explanation:

CFX is just a larger version of AEX. Same thing with CFX.

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Explain how double angles compare to parent trigonometric equations

Ne4ueva [31]

Special cases of the sum and difference formulas for sine and cosine yields what is known as the double‐angle identities and the half‐angle identities.

7 0

3 years ago

Home help plz really appreciate it!!!!!

Schach [20]

Answer:

angle AGE=113.5

Step-by-step explanation:

3x-28=66-x

4x=94

x=23.5

23.5+90=113.5

4 0

3 years ago

Read 2 more answers

Which equations are true for x = -2 and x = 2? Select two options

Flauer [41]

Answer:

A and C

Step-by-step explanation:

solving the equations

x² - 4 = 0 ( add 4 to both sides )

x² = 4 ( take square root of both sides )

x = ± $\sqrt{4}$ = ± 2 ← required solution

x² = - 4 ← has no real solutions

4x² = 16 ( divide both sides by 4 )

x² = 4 ( take square root of both sides )

x = ± $\sqrt{4}$ = ± 2 ← required solution

2(x - 2)² = 0 , then

x- 2 = 0 ( add 2 to both sides )

x = 2 ← not the required solution

5 0

2 years ago

Read 2 more answers

A hoop, a uniform solid cylinder, a spherical shell, and a uniform solid sphere are released from rest at the top of an incline.

Serjik [45]

Answer:

Step-by-step explanation:

Given

Hoop, Uniform Solid Cylinder, Spherical shell and a uniform Solid sphere released from Rest from same height

Suppose they have same mass and radius

time Period is given by

$t=\sqrt{\frac{2h}{a}}$ ,where h=height of release

a=acceleration

$a=\frac{g\sin \theta }{1+\frac{I}{mr^2}}$

Where I=moment of inertia

a for hoop

$a=\frac{g\sin \theta }{1+\frac{mr^2}{mr^2}}$

$a=\frac{g\sin \theta }{2}$

a for Uniform solid cylinder

$a=\frac{g\sin \theta }{1+\frac{mr^2}{2mr^2}}$

$a=\frac{2g\sin \theta }{3}$

a for spherical shell

$a=\frac{g\sin \theta }{1+\frac{2mr^2}{3mr^2}}$

$a=\frac{3g\sin \theta }{5}$

a for Uniform Solid

$a=\frac{g\sin \theta }{1+\frac{2mr^2}{5mr^2}}$

$a=\frac{5g\sin \theta }{7}$

time taken will be inversely proportional to the square root of acceleration

$t_1=k\sqrt{2}=1.414k$

$t_2=k\sqrt{\frac{3}{2}}=1.224k$

$t_3=k\sqrt{\frac{5}{3}}=1.2909k$

$t_4=k\sqrt{\frac{7}{5}}=1.183k$

thus first one to reach is Solid Sphere

second is Uniform solid cylinder

third is Spherical Shell

Fourth is hoop

3 0

3 years ago

Will give brainlyest if u help

goblinko [34]

Answer:

No, because it fails the vertical line test ⇒ B

Step-by-step explanation:

To check if the graph represents a function or not, use the vertical line test

Vertical line test: Draw a vertical line to cuts the graph in different positions,

if the line cuts the graph at just one point in all positions, then the graph represents a function

if the line cuts the graph at more than one point in any position, then the graph does not represent a function

In the given figure

→ Draw vertical line passes through points 2, 6, 7 to cuts the graph

∵ The vertical line at x = 2 cuts the graph at two points

∵ The vertical line at x = 6 cuts the graph at two points

∵ The vertical line at x = 7 cuts the graph at one point

→ That means the vertical line cuts the graph at more than 1 point

in some positions

∴ The graph does not represent a function because it fails the vertical

line test

7 0

3 years ago