Answer: The difference present between the packet switching and circuit switching are as follows:-
- Packet switching i the switching in which the data packet travels through the connectionless path whereas connection oriented routes are present for circuit switching
- Network layer uses the feature of packet switching while physical layer uses circuit switching technique
- Data transferring is mostly preferred through packet switching and voice communication takes place through the circuit switching.
- Packet switching is considered flexible as no already established connection is present for switching but the connection in circuit switching are already defined which makes it less flexible.
Among the packet switching and circuit switching , packet switching is preferred for the communication through the data packets because they have flexibility and affordability.It can establish numerous connection for switching and this make it efficient.
The PDU that is processed when a host computer is de-encapsulating a message at the transport layer of the tcp/ip model is segment.
<h3>What is this PDU about?</h3>
Note that in the transport layer, a host computer is said to often de-encapsulate what we call a segment so that they can be able to put back data to an acceptable or given format through the use of the application layer protocol that belongs to the TCP/IP model.
Therefore, The PDU that is processed when a host computer is de-encapsulating a message at the transport layer of the tcp/ip model is segment as it is the right thing to do.
Learn more about host computer from
brainly.com/question/553980
Answer:
Achieved Instruction per cycle rate is 
Solution:
As per the question:
Execution time, t = 1.4 s
No. of instructions being executed, n = 1.8 billion =
Clock speed of CPU, f = 3.2 GHz = 
Now, to calculate the actual issue rate achieved:
CPI (Cycle per Instruction) = 
CPI = 
Instruction per cycle is given as the reciprocal of CPI:
Instruction per cycle = 
Answer: This element needs 3 electrons to complete its octet state
Why?:
since the electrons in 2s2 are already paired they cannot form a bond pair with electrons from other elements without hybridisation however the 3 electrons in 2p3 are unpaired so can form bond pairs with electrons from other elements without hybridisation.
Hope this helps!