the standard equation of the circle having the given center and radius is
.
Answer:
P____Q____R
PR= PQ+ QR
(14x-13) = (5x-2)+(6x+1)
14x-13= 11x – 1
14x – 11x = 13–1
3x = 12
x= 12/ 3
x= 4
PR= 14x – 13 = 14 (4) – 13 = 18 – 13= 5
If you want (PQ , QR ) this is the solution
PQ =5x-2=5(4)-2=20-2=18
QR =6x+1=6(4)+1=24+1=25
I hope I helped you^_^
Step-by-step explanation:
x²-3x +5x -15=33
x²-3x+5x=33+15
x²-3x+5x=48
x²+2x=48
divide both sides by 2
x²+x =24
x²= 24
x= ✓24
dunno from here
Answer:
7
Step-by-step explanation:
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