Answer:
Option (2)
Step-by-step explanation:
Step 1.
![\sqrt{(\text{cosA-cosB})^2+(\text{sinA-sinB})^2}=\sqrt{(cos(A-B)-1)^2+(sin(A-B)-0)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28%5Ctext%7BcosA-cosB%7D%29%5E2%2B%28%5Ctext%7BsinA-sinB%7D%29%5E2%7D%3D%5Csqrt%7B%28cos%28A-B%29-1%29%5E2%2B%28sin%28A-B%29-0%29%5E2%7D)
Step 2.
(cosA - cosB)² + (sinA - sinB)² = [cos(A - B) - 1]² + [sin(A - B) - 0]²
Step 3.
cos²A + cos²B - 2cosAcosB + sin²A + sin²B - 2sinAsinB = cos²(A - B) + 1 - 2cos(A - B) + sin²(A - B)
Step 4.
2 - 2cosAcosB - 2sinAsinB = 1 - 2cos(A - B) + 1
Step 5.
cosAcosB + sinAsinB = cos(A - B)
Therefore, Option (2) will be the answer.
Answer:
g(x) =f(x+4) +8
Step-by-step explanation:
rewrite the g in terms of f
Answer:
Probability of event = 0.28
Step-by-step explanation:
At a fundraiser, a school group charges $8 for tickets for a "grab bag".
You choose one bill at random from a bag that contains 36 $1 bills, 19 $5 bills, 6 $10 bills, 7 $20 bills, and 3 $100 bills.
The total number of bills = 36 + 19 + 6 + 7 +3 =71 bills.
We have to find the probability that i will be able to win enough to pay my ticket that is he must get at least $8.
The price would be sufficient if he gets $10, $20 or $100 bills.
So the favorable cases = 20
Total cases = 71
hence probability =
= 0.28
The probability of him getting price greater than his ticket = 0.28
Answer:
that's an equation
Step-by-step explanation: