7. What is the value of x for the triangle drawn below?

Would like to k ow the answer ?!

Arlecino [84]

Answer:

yessirrr cuz ion kno the answer to this question

..

3 0

3 years ago

Which one of the quotients is correct? A) 876 ÷ 43 = 20r17B) 876 ÷ 43 = 20r16C) 876 ÷ 43 = 20r7D) 876 ÷ 43 = 20r6

Olegator [25]

To check which of the quotients is correct, multiply 43 times 20 and add the remainder. The result must be equal to 876.

First, notice that 20 times 43 equals 860.

A)

The remainder is 17. 860 + 17 = 877, which is not equal to 876.

B)

The remainder is 16. 860 + 16 = 876, which is equal to 876.

C)

The remander is 7. 860 + 7 = 867, which is not equal to 876.

D)

The remainder is 6. 860 + 6 = 866, which is not equal to 876.

Since 20*43 + 16 = 876, then the correct quotient is shown in option B:

876 ÷ 43 = 20 r 16

4 0

1 year ago

The number and frequency of Atlantic hurricanes annually from 1940 through 2007 is shown here:

klio [65]

Answer:

The probability table is shown below.

A Poisson distribution can be used to approximate the model of the number of hurricanes each season.

Step-by-step explanation:

(a)

The formula to compute the probability of an event E is:

$P(E)=\frac{Favorable\ no.\ of\ frequencies}{Total\ NO.\ of\ frequencies}$

Use this formula to compute the probabilities of 0 - 8 hurricanes each season.

The table for the probabilities is shown below.

(b)

Compute the mean number of hurricanes per season as follows:

$E(X)=\frac{\sum x f_{x}}{\sum f_{x}}=\frac{176}{68}= 2.5882\approx2.59$

If the variable X follows a Poisson distribution with parameter λ = 7.56 then the probability function is:

$P(X=x)=\frac{e^{-2.59}(2.59)^{x}}{x!} ;\ x=0, 1, 2,...$

Compute the probability of X = 0 as follows:

$P(X=0)=\frac{e^{-2.59}(2.59)^{0}}{0!} =\frac{0.075\times1}{1}=0.075$

Compute the probability of X = 1 as follows:

$\neq P(X=1)=\frac{e^{-2.59}(2.59)^{1}}{1!} =\frac{0.075\times7.56}{1}=0.1943$

Compute the probabilities for the rest of the values of X in the similar way.

The probabilities are shown in the table.

On comparing the two probability tables, it can be seen that the Poisson distribution can be used to approximate the distribution of the number of hurricanes each season. This is because for every value of X the Poisson probability is approximately equal to the empirical probability.