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icang [17]
4 years ago
12

A) AAS C) ASA B) SSS D) SAS

Mathematics
2 answers:
scoray [572]4 years ago
8 0
What’s the question??
Tema [17]4 years ago
5 0

Answer:

what is the question or link

Step-by-step explanation:

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The length of a rectangular garden is 8 feet longer than it’s width. The garden is surrounded by a sidewalk that is 4 feet wide
Westkost [7]
Answer:

The length = 20
The width = 12 

Explanation:

Let the Length of the garden be L and the Width W 
Therefore the area of the garden = L*W 
But we know that L = W + 8 
Therefore the area of the garden can be expressed as W*(W + 8) 
When the brackets are expanded this equals W^2 + 8W

The area of the recctangle which includes the path and garden will have a length of L + 8 (ie the length of the garden + 4 feet at the top and 4 feet at the bottom) 
The width will be W + 8 (width of garden + 4 feet at the left and 4 feet at the right) 
Therefore the area will be (W + 8)*(L +8) 
Once again we know that L = W + 8 
Therefore the area of the path/garden = (W +8)(W +8 +8) 
=(W +8)(W +16) 
=W^2 +24W + 128 

We know that the path alone has an area of 320 square feet. Therefore if we subtract the area of the garden (W^2 + 8W) from the area of the path/garden the area left is the area of the path only 

Therefore W^2 + 24W + 128 - (W^2 + 8W) = 320 
W^2 + 24W + 128 - W^2 - 8W = 320 
Simplify 
16W + 128 = 320 
Subtract 128 from both sides of the equation 
16W = 192 
divide both sides of the equation by 16 
W = 12 
As L = W + 8 
L = 12 + 8 = 20 
7 0
3 years ago
What is the perimeter of the composite figure?
Ket [755]

Answer:

0.33yd is perimeter

Step-by-step explanation:

perimeter of composite figure =4.6+4.6+7+7+7=30.2 cm=0.33yd

3 0
3 years ago
Read 2 more answers
0.5401 this in scientific notation
bearhunter [10]
5.401 x -10
hope i can help, of so may i have brainliest, i want my level up
4 0
3 years ago
Read 2 more answers
Beverly made a deposit of 375 into our checking account. Then she
777dan777 [17]

Answer:

650

Step-by-step explanation:

475+375-65-135=650

8 0
3 years ago
Two vehicles, a car and a truck, leave an intersection at the same time. The car heads east at an average speed of 30 miles per
svet-max [94.6K]
I don’t fully understand but you might be able to do something like

70t -30t = d, but I think that would be how much farther they are from the start point, but assuming they are driving in a straight line or would be a right triangle, so maybe The square root of 70t^2 + 30t^2
8 0
3 years ago
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