
When the exponent is negative, you have to make the number a fraction(1 over the number).
For example:


This gets rid of the negative, but it leaves the exponent

When an exponent is a fraction, it is the square root.
For example:
![x^{\frac{1}{3}} = \sqrt[3]{x}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%20%3D%20%20%5Csqrt%5B3%5D%7Bx%7D)

![x^{\frac{1}{4}}=\sqrt[4]{x}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%3D%5Csqrt%5B4%5D%7Bx%7D)
So...

Answer:
Option b is correct.
Step-by-step explanation:
From the given condition : Seven less than the quotient of a number, x, and twelve is five times the number.
Here, the number is x
The quotient of a number x and twelve is expressed as , 
Seven less than the quotient of a number, x, and twelve is expressed as, 
Five times the number mean, 
Therefore, we have an equation in the form of <em>x</em> from the given condition as:
.
Hey there! I'm happy to help!
We know that the perimeter is 2L+2W. Le'ts plug in the values 3 and 5 from our ratio and see what our perimeter would be with that.
2(3)+2(5)
6+10
16
How can we get this 16 to 64?
64/16=4
So, we need to multiply this length and width by four to get 64 as our perimeter!
3*4=12
5*4=20
We can plug this into our perimeter equation
2(12)+2(20)
24+40
64
Therefore, our length is 12 and our width is 20.
Have a wonderful day! :D
Answer:
The line should begin on the right side 2 dashes (the small lines tht go throught the number line. There are 9 dashes between each whole number.)
Then the line should go left because it says x is less than 2/9. (which is right)
The line segment you should choose is the one with the open circle with an arrow going to the left.
<---O (looks like this lol.)