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Arisa [49]
3 years ago
8

3. What is the last step to complete a perpendicular bisector construction? *

Mathematics
1 answer:
Furkat [3]3 years ago
6 0

Its

C. Draw a line connecting the the intersection of the arcs below and above the segment.

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Yamri went to the store to buy gardening supplies. A bag of dirt was $3.99 and tulips cost 75 cents per bulb. He bought one bag
seraphim [82]
3.99 + 0.75b = 12.24
0.75b = 12.24 - 3.99
0.75b = 8.25
b = 8.25 / 0.75
b = 11.....there were 11 bulbs
8 0
3 years ago
Read 2 more answers
In the rhombus m<1 =160. What are m<2 and m<3? The diagram isn't drawn to scale
Zolol [24]
A rhombus is a parallelogram with four equal sides and two sets of equal angles.

If the m<1=160°, then the angle opposite (3) would also be 160°.

m<3=160°.

Becuase it is a parallelogram, the sum of the measurment of two angles that share a line would be 180 (supplementary).

m<2 and m<4 is 20°.
5 0
3 years ago
BRAINLIST
777dan777 [17]
Answer:

Naomi must buy a minimum of 5 blocks of cream cheese.


Explanation:

2.75 pounds = 44 ounces

44 oz divided by 8 oz (per block) =
5.5 blocks of cream cheese

She already has 4 oz of cream cheese so subtract 1/2 block of cream cheese.

She needs to buy at least 5 blocks.


5 0
3 years ago
Read 2 more answers
What is true about the completely simplified sum of the polynomials 3x squared y squared minus 2 x y to the power of 5 and negat
12345 [234]

Answer:

The sum is a binomial with a degree of 6.

Step-by-step explanation:

To find : What is true about the completely simplified sum of the polynomials 3x^2y^2-2xy^5 and -3x^2y^2+3x^4y ?

Solution :

The polynomials  3x^2y^2-2xy^5 and -3x^2y^2+3x^4y ,

The sum of polynomial is given by,

S=3x^2y^2-2xy^5+(-3x^2y^2+3x^4y)

On simplifying , we get,

S=3x^2y^2-2xy^5-3x^2y^2+3x^4y

S=-2xy^5+3x^4y

Therefore, the result obtained is a binomial with a degree of 6.

4 0
3 years ago
33 1/3% of 75<br><br>plz help​
Paraphin [41]

The answer is 25

x 33 1/3% = 75

75 / 33 1/3

0.3333

(75)(0.333) =  25

24.9999999 rounds to 25

Hope this helps, have a BLESSED day! :-)

6 0
3 years ago
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