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Stella [2.4K]
3 years ago
9

A gold chain with an original price of $120 is on sale for $96. What is the percent of the discount?

Mathematics
2 answers:
svet-max [94.6K]3 years ago
8 0

Answer:

Step-by-step explanation:

percent discount=(120-96)/120 ×100

=24/120×100=20  %

bixtya [17]3 years ago
3 0

Answer:

25

Step-by-step explanation:

Because he only took of all little bit of cash hope this helps

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5) Is 3 a zero (or root) of f(x) = x3 - 9x2 + 11x + 21?
frozen [14]

Answer:

Yes

Step-by-step explanation:

f(x) = x³ − 9x² + 11x + 21

f(3) = (3)³ − 9(3)² + 11(3) + 21

f(3) = 27 − 81 + 33 + 21

f(3) = 0

6 0
3 years ago
In the expression z-2t+49-q, what is 49 called?
ZanzabumX [31]
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A particle is projected with a velocity of <img src="https://tex.z-dn.net/?f=40ms%5E-%5E1" id="TexFormula1" title="40ms^-^1" alt
Katena32 [7]

Answer:

2\sqrt{55}\text{ m/s or }\approx 14.8\text{m/s}

Step-by-step explanation:

The vertical component of the initial launch can be found using basic trigonometry. In any right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse. Let the vertical component at launch be y. The magnitude of 40\text{ m/s} will be the hypotenuse, and the relevant angle is the angle to the horizontal at launch. Since we're given that the angle of elevation is 60^{\circ}, we have:

\sin 60^{\circ}=\frac{y}{40},\\y=40\sin 60^{\circ},\\y=20\sqrt{3}(Recall that \sin 60^{\circ}=\frac{\sqrt{3}}{2})

Now that we've found the vertical component of the velocity and launch, we can use kinematics equation v_f^2=v_i^2+2a\Delta y to solve this problem, where v_f/v_i is final and initial velocity, respectively, a is acceleration, and \Delta y is distance travelled. The only acceleration is acceleration due to gravity, which is approximately 9.8\:\mathrm{m/s^2}. However, since the projectile is moving up and gravity is pulling down, acceleration should be negative, represent the direction of the acceleration.

What we know:

  • v_i=20\sqrt{3}\text{ m/s}
  • a=-9.8\:\mathrm{m/s^2}
  • \Delta y =50\text{ m}

Solving for v_f:

v_f^2=(20\sqrt{3})^2+2(-9.8)(50),\\v_f^2=1200-980,\\v_f^2=220,\\v_f=\sqrt{220}=\boxed{2\sqrt{55}\text{ m/s}}

3 0
3 years ago
Kari has $400 in a savings account the interest rate is 10% compounded annually which type of model best fits this situation
Mumz [18]

Answer:

What model?

Step-by-step explanation:

4 0
3 years ago
Simplify to create a equivalent expression.
Ratling [72]

Answer:

\boxed{\bold{66k+9}}

Explanation:

Expand \bold{5\left(10k+1\right): \ 50k+5}

= \bold{50k+5+2\left(2+8k\right)}

Expand \bold{2\left(2+8k\right): \ 4+16k}

= \bold{50k+5+4+16k}

Simplify \bold{50k+5+4+16k: \ 66k+9}

= \bold{66k+9}

Mordancy.

7 0
3 years ago
Read 2 more answers
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