Answer:
With a BB homozygous the probability of a gamete having the B allele is 100%, and no chance of having the b allele.
Explanation:
For a given trait, B represents the dominant allele, while b is the recessive one. The fact that an individual has a homozygous (dominant) form for this trait means that their homologous chromosomes contain the B allele and, therefore, his gametes can only have the B allele.
In the case that the individual was heterozygous, the chances of having a gamete with B or b would be 50:50.
Learn more:
Homologous chromosomes with heterozygous or homozygous alleles brainly.com/question/210889
Your answer is going to be D
Answer:
See the answer below
Explanation:
<em>Genotype is the genetic composition of organisms and a gene is made up of two alleles.</em>
a) Since the allele for black is B, <u>the genotype for black chickens would be BB. </u>
b) Since the allele for white is W, <u>the genotype for white chickens would be WW.</u>
c) Since erminette color is heterozygous,<u> the genotype would be BW.</u>
d) Two erminette were crossed:
BW x BW
BB BW BW WW
i. <em>Probability of having black chick (BB) </em>= 1/4
ii. <em>Probability of having a white chick (WW)</em> = 1/4
iii. <em>Probability of having erminette chicken (BW)</em> = 1/2
Answer:
Speciation was allopatric or peripatric, but would depend on the number of individuals that dispersed from the original populations.
Explanation:
- There are two types of speciation: allopatric and peripatric.
- Allopatric speciation occurs when the species of same population gets isolated that results in lack of gene flow.
- From the isolated population, new species are formed then it is known as the peripatric speciation.
- All these isolation of populations and formation of new species depends upon the initial or original group of species that was dispersed.
