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balandron [24]
3 years ago
7

What is the IQR (Inter Quartile Range) for the data set? 11 6 19 14 21 7 13 15 15 Question 10 options: 8 9 15 17

Mathematics
1 answer:
Gnesinka [82]3 years ago
7 0
IQR is the Q3 - Q1 

Put the data in order.....

6, 7, 11, 13, 14, 15, 15, 19, 21 
       ^             ^             ^  
      9(Q1)     14(Q2)    17(Q3) 

17 (Q3) - 9 (Q1) = 8 (IQR) 

So the answer to your question is the first option, 8. 

Hope this helps! :D



       
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Please help!
mariarad [96]

Answer: 1,045 passengers

Step-by-step explanation:

This question involves multiple steps. Let's first try to figure the number of children on the cruise.

The ratio of girls to the total number of children was 2:5. There are 198 boys.

This information tells me that for every 5 children, there's 2 girls and 3 boys.

Based off of this information, we can divide the total number of boys by 3 in order to find the number of children.

198÷3=66

Let's multiply 66 by 5 since that's the number of groupings based off the ratio.

66×5=330

Let's check the number of children. Since the ratio of girls to total children is 2:5 and we already confirmed there's 198 boys, there should be 132 girls. We can turn this ratio into a fraction where 2/5 of the children are girls. we can confirm this by multiply 330 by 2/5 (0.4) and getting 132.

There are 330 children on the cruise.

The ratio of the number of adults to the number of children was 13:6.

For every 6 children, there were 13 adults. Let's divide the number of children by 6 in order to find the number of groupings.

330÷6=55

Let's now multiply the groupings by 13 to find the number of adults.

55×13=715

So there should be 715 adults and 330 children on the cruise.

715+330=1,045

5 0
3 years ago
The humidity dropped an average of 1 1/3% each hour over the last six hours. What was the total change in humidity?
Zolol [24]
14 times 6

6 times 14
3 0
3 years ago
A factor in determining the usefulness of an examination as a measure of demonstrated ability is the amount of spread that occur
GarryVolchara [31]

Answer:

Step-by-step explanation:

From the information given :

The null hypothesis H_o : \sigma = 60

The alternative hypothesis  Ha : \sigma \neq 60

Given that:

the sample size n = 21

sample standard deviation s = 68

population standard deviation σ = 60

a) The level of significance \alpha =0.01

b) The chi-square statistics can be calculated as:

\bar X = \dfrac{(n-1)s^2}{\sigma^2}

\bar X = \dfrac{(21-1)68^2}{60^2}

\bar X = \dfrac{(20)4624}{3600}

\bar X = 25.69

The degree of freedom is :

= n - 1

= 21 - 1

= 20

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3 years ago
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