Add 4 to both sides
x - 4 < -3
x-4+4 < -3+4
x < 1
To graph this on a number line, plot an open circle at 1 on the number line. Do not fill in the open circle. Shade to the left of the open circle. The shaded region represents all x values smaller than 1.
The graph is shown below.
The expression for 7 less than the product of a number and 8, increased by a number multiplied by 2 is 8n-7 +2n
Given :
7 less than the product of a number and 8, increased by a number multiplied by 2
We need to write the given statement in an expression
Lets 'n' be the unknown number
the product of a number and 8
Product means multiplication
the product of a number and 8 mean n times 8 that is 8n
7 less than the product of a number and 8, subtract 7 from 8n
Expression becomes 8n-7
This is increased by a number multiplied by 2
number multiplied by 2 is 2n
So the final expression for the given statement is 8n-7 +2n
Learn more : brainly.ph/question/1023996
Answer:
The answer to your question is: ( x + 6 ) ( x - 2 )
Step-by-step explanation:
Factor x² + 4x - 12 = 0
Find two numbers that added gives +4 and if we multiply them get -12
We can find these numbers by decomposing -12 in its prime factors
12 2
6 2 12 = 2 x 2 x 3
3 3 now combine the numbers to get -12 and + 4
1 2 and 2 x 3 = 6
and 2 x 6 = 12
Then
( x + 6 ) ( x - 2 )
9514 1404 393
Answer:
the difference of 2 or 3 rectangles
Step-by-step explanation:
In every case, the "shaded" area can be computed by finding the area of a "bounding" rectangle, and subtracting the areas of the rectangular cutouts that give the figure its shape.
(a) The cutout is the white space at upper right. (Insufficient dimensions are given.)
(b) The cutout is the white space at lower left. The bounding rectangle is 8×7, and the cutout is 4×3.
(c) The cutout is the rectangle in the middle. The bounding rectangle is 13×7, and the cutout is 4×1.
(d) The cutouts are the rectangles on either side. They could be considered as a single unit. The bounding rectangle is 20×25; the cutouts have a total width of 16 and a height of 20, so total 16×20.
(e) Similar to (d), the cutouts are the white spaces on either side. The bounding rectangle is 14×12. The cutouts total 12 in width and 3 in height, so total 12×3.
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You will note in (d) and (e) that the dimensions of the cutouts have something in common with the dimensions of the bounding rectangle. This means the problem can be simplified a little bit by factoring out that common factor. In (e), for example, 14×12 -(12×3) = 12(14 -3) = 12×11
