Answer:
19.04
Step-by-step explanation:
find the length of AB,BC,CD , and AD
distance=√(x2-x1)^2+(y2-y1)^2
A(-3,5), B(2,6),C(0,2),D(-5,1)
line AB :d=√(2−(−3))^2+(6−6)^2
AB=5
BC=d=√(0−2)^2+(2−6)^2=√20=2√5
CD:√26
DA:√20
perimeter=AB+BC+CD+DA=5+√20+√20+√26=19.04
DE
See how DE cuts through half? We shouldn't be too accurate for the midsegment.
The range is from 4 to -2 is 6
