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Lady bird [3.3K]
3 years ago
10

How does the strong nuclear force hold the nucleus of an atom together?iuhh

Mathematics
2 answers:
3241004551 [841]3 years ago
8 0

Answer: The strong nuclear force, also called binding energy, holds quarks together to form protons and neutrons. Residual binding energy, also called the nuclear force, holds protons and neutrons together to form the nucleus of an atom.

This holds true up to about atomic number 83 (bismuth), at which point the electromagnetic force, a repulsive force for protons, starts to overcome the distance barrier of binding energy and make the nucleus unstable. This makes the atoms starting at bismuth and above be radioactive.

Additionally, the presence or absence of extra neutrons, i.e. isotopes, even in light nuclides, can, due to the weak interaction, makes the nucleus be unstable, and radioactive.

Tresset [83]3 years ago
6 0

Answer:

The strong nuclear force holds together the quarks and gluons within protons and neutrons. It also holds together the protons and neutrons within the nucleus of the atom.

Step-by-step explanation:

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In triangleABC, C is the right angle. If tanA = 8/6, find cosB
klemol [59]

<u>Short answer</u> = C) 8/10

<u>Working :</u>

Tan A = 8/6 = Opposite / AdjacentOpposite = 8 units

Adjacent = 6 units

Hypotenuse = \sqrt{8^{2} + 6^{2} }

                     = \sqrt{64 + 36 }

                     = \sqrt{100}

                     = 10 units

Cos B  = Adjacent/ Hypotenuse

        ∴  cos B= 8/10

4 0
4 years ago
Can someone walk me through this?
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Answr :

I hope my answer is correct

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5 0
3 years ago
(NEED HELP 100 POINTS IF ANSWERED) Fill in the blank
Vaselesa [24]

Answer:

The answer is 5.

Step-by-step explanation:

(2x+3)(x+1) Use the FOIL METHOD

2x²+2x+3x+3

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3 0
3 years ago
Read 2 more answers
Find the exact value of the indicated trigonometric function of θ.
Mariana [72]

Answer:

cosθ = -√(35/36)

tanθ = -1/√35

Step-by-step explanation:

We know that

sin²θ + cos²θ = 1

(1/6)² + cos²θ = 1

1 - (1/6)² = cos²θ

35/36 = cos²θ

sec θ = 1/ cosθ

1/ secθ = cos θ

Because secθ < 0, 1/ secθ would also be < 0, so cos θ < 0

cosθ = -√(35/36)

tanθ = sinθ/cosθ = (1/6)/-√(35/36)

= (1/6) / -(√35/6)

= -1/√35

8 0
3 years ago
Crystal is on page 88 in her book and will read 20 pages every day until she finishes it . Which expression tells us what page s
12345 [234]

Answer: The required expression she is on after d days is 88+20d

Step-by-step explanation:

Since we have given that

Page number at which she is = 88

Number of pages she will read every day = 20

Let the number of days be 'x'.

According to question, it becomes

y=88+20d

Hence, the required expression she is on after d days is 88+20d

6 0
4 years ago
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