First we need to determine what the 6 angles must add to. Turns out we use this formula
S = 180(n-2)
where S is the sum of the angles (result of adding them all up) and n is the number of sides. In this case, n = 6. So let's plug that in to get
S = 180(n-2)
S = 180(6-2)
S = 180(4)
S = 720
The six angles, whatever they are individually, add to 720 degrees. The six angles are y, y, 2y-20, 2y-20, 2y-20, 2y-20, <span>
They add up and must be equal to 720, so let's set up the equation to get...
(y)+(y)+(</span>2y-20)+(2y-20)+(2y-20)+(<span>2y-20) = 720
Let's solve for y
</span>y+y+2y-20+2y-20+2y-20+2y-20 = 720
10y-80 = 720
10y-80+80 = 720+80
<span>10y = 800
</span>
10y/10 = 800/10
y = 80
Now that we know the value of y, we can figure out the six angles
angle1 = y = 80 degrees
<span>angle2 = y = 80 degrees
</span><span>angle3 = 2y-20 = 2*80-20 = 140 degrees
</span>angle4 = 2y-20 = 2*80-20 =<span> 140 degrees
</span><span>angle5 = 2y-20 = 2*80-20 = 140 degrees
</span>angle6 = 2y-20 = 2*80-20 =<span> 140 degrees
</span>
and that's all there is to it
Answer:
Step-by-step explanation:
A.f(x) =(x-1)^2 is even because of that even exponent, 2.
b. F(x)=8x is odd because x has the exponent 1.
c.f(x) =x^2-x is neither even nor odd
d.f(x)=7 is even because the exponent is even: 7^0
I think it would be 117
Because H is 63
So 90+90+63=243
360-243=117
I used 360 because angles in quadrilaterals add up to 360 degrees
Step-by-step explanation:
Answer:
(4b-1)*(8a-7)
Step-by-step explanation:
