A survey was done to determine the effect of students changing answers while taking a multiple-choice test on which there is on
1 answer:
Answer:
6% of the changes were from incorrect to incorrect
Step-by-step explanation:
The sum of the percentages must be 100%.
We have these following percentages
65% of the changes were from incorrect answers to correct
29% were from correct to incorrect
P% were from incorrect to incorrect
So
6% of the changes were from incorrect to incorrect
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Answer:
The margin of error for a 99% confidence interval for the population mean is 1.8025.
Step-by-step explanation:
We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of .
So it is z with a pvalue of , so
Now, find the margin of error M as such
In which is the standard deviation of the population and n is the size of the sample.
In this problem:
So
The margin of error for a 99% confidence interval for the population mean is 1.8025.