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3 years ago

I need help with this please!

Mathematics

1 answer:

12345 [234]3 years ago

4 0

Answer:

ok. i don't understand this so could u be more specific and tell me what's ur problem

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Is quadrilateral jklm the result of a dilation of quadrilateral abcd by a scale factor of 2? why or why not?

4vir4ik [10]

No. Because sides JM and KL have different slopes from sides AD and BC .

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

For AD:

We have the points A(2, -2) and D(1, -4). Substitute:

$m=\dfrac{-4-(-2)}{1-2}=\dfrac{-2}{-1}=2$

For JM:

We have the points J(4, -4) and M(2, -9). Substitute:

$m=\dfrac{-9-(-4)}{2-4}=\dfrac{-5}{-2}=2.5$

$2\neq2.5$

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Another argument.

No. Because the MJ is not twice as long as AD.

The formula of the length of a segment:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The length of AD:

$|AD|=\sqrt{(1-2)^2+(-4-(-2))^2}=\sqrt{(-1)^2+(-2)^2}=\sqrt{1+4}=\sqrt5$

The length of MJ:

$|MJ|=\sqrt{(2-4)^2+(-9-(-4))^2}=\sqrt{(-2)^2+(-5)^2}=\sqrt{4+25}=\sqrt{29}$

$\sqrt{29}\neq2\sqrt5$

4 0

4 years ago

Write an equation for each circle

Alinara [238K]

Yep what the girl said

5 0

3 years ago

Find the solutions of the equation x4 − 2x3 − x2 + 2x = 0. (Enter your answers as a comma-separated list.)

Bad White [126]

Answer:

$S=\left \{ 0,-1,1,2 \right \}$

Step-by-step explanation:

There are several ways to solve this quartic equation. But since the coefficients, they repeat a=1,b=2,c=1,d=2, but e=0, and they are multiple of each other, then it is more convenient to work with factoring as the method of solving it.

As if it was a quadratic one.

$x^{4}-2x^{3}- x^{2} + 2x = 0\\x(x^{3}-2x^{2}-x+2)=0 \:Factoring \:out\\x[(x^{3}-2x^{2})+(-x+2)]=0 \:Grouping\\x[\mathbf{x^{2}}(x-2)+\mathbf{-1}(x+2)]=0 \:Rewriting\:the\:first\:factor\\x(x^{2}-1)(x-2)\:Expanding \:the \:first \:factor\\x(x-1)(x+1)(x-2)=0\\x=0,x=1,x=-1,x=2\\S=\left \{ 0,-1,1,2 \right \}$