Answer:
α = π/3
β = π/6
Explanation:
Use arc length equation to find the sum of the angles.
s = rθ
π/20 m = (0.1 m) (α + β)
π/2 = α + β
Draw a free body diagram for each sphere. Both spheres have three forces acting on them:
Weight force mg pulling down,
Normal force N pushing perpendicular to the surface,
and tension force T pulling tangential to the surface.
Sum of forces on A in the tangential direction:
∑F = ma
T − m₁g sin α = 0
T = m₁g sin α
Sum of forces on B in the tangential direction:
∑F = ma
T − m₂g sin β = 0
T = m₂g sin β
Substituting:
m₁g sin α = m₂g sin β
m₁ sin α = m₂ sin β
(1 kg) sin α = (√3 kg) sin (π/2 − α)
1 sin α = √3 cos α
tan α = √3
α = π/3
β = π/6
Answer:
D.
a heat force generated by the flames
Explanation:
Im not sure if that is right. the answer also maybe C.
In the vertical direction, take up to be positive and down to be negative. Then the net <u>vertical</u> force would be
5120 N - 4050 N = 1070 N
(it's positive, so the net vertical force is pointing upward)
In the horizontal direction, take right to be positive and left to be negative. Then the net <u>horizontal</u> force would be
950 N - 1520 N = -570 N
(negative means the net horizontal force points to the left)
So the net force on the balloon is the vector
<em>F</em> = (1070 N) <em>i</em> + (-570 N) <em>j</em>
(where <em>i</em> and <em>j</em> are the unit vectors in the horizontal and vertical directions, respectively)
The magnitude of the net force on the balloon is the magnitude of this vector:
<em>F</em> = √((1070 N)² + (-570 N)²)
<em>F</em> ≈ 1212 N
This is beacuse it is caused by light scattering of light in the atmosphere. When the moon rises blue light is caused and scattered also caused by earth's atmosphere and it is black on the moon as there is no lunar atmosphere , so no light scattering.
True is the correct answer hope this helps
