Answer:
B :)
Explanation:
:) JUST TRUST ME I GOT IT CORRECT
Answer : The volume of a sample of 4.00 mol of copper is ![28.5cm^3](https://tex.z-dn.net/?f=28.5cm%5E3)
Explanation :
First we have to calculate the mass of copper.
![\text{ Mass of copper}=\text{ Moles of copper}\times \text{ Molar mass of copper}](https://tex.z-dn.net/?f=%5Ctext%7B%20Mass%20of%20copper%7D%3D%5Ctext%7B%20Moles%20of%20copper%7D%5Ctimes%20%5Ctext%7B%20Molar%20mass%20of%20copper%7D)
![\text{ Mass of copper}=(4.00moles)\times (63.5g/mole)=254g](https://tex.z-dn.net/?f=%5Ctext%7B%20Mass%20of%20copper%7D%3D%284.00moles%29%5Ctimes%20%2863.5g%2Fmole%29%3D254g)
Now we have to calculate the volume of copper.
Formula used :
![Density=\frac{Mass}{Volume}](https://tex.z-dn.net/?f=Density%3D%5Cfrac%7BMass%7D%7BVolume%7D)
Now put all the given values in this formula, we get:
![8.92\times 10^3kg/m^3=\frac{254g}{Volume}](https://tex.z-dn.net/?f=8.92%5Ctimes%2010%5E3kg%2Fm%5E3%3D%5Cfrac%7B254g%7D%7BVolume%7D)
![Volume=\frac{254g}{8.92\times 10^3kg/m^3}=2.85\times 10^{-2}L=2.85\times 10^{-2}\times 10^3cm^3=28.5cm^3](https://tex.z-dn.net/?f=Volume%3D%5Cfrac%7B254g%7D%7B8.92%5Ctimes%2010%5E3kg%2Fm%5E3%7D%3D2.85%5Ctimes%2010%5E%7B-2%7DL%3D2.85%5Ctimes%2010%5E%7B-2%7D%5Ctimes%2010%5E3cm%5E3%3D28.5cm%5E3)
Conversion used :
![1kg/m^3=1g/L\\\\1L=10^3cm^3](https://tex.z-dn.net/?f=1kg%2Fm%5E3%3D1g%2FL%5C%5C%5C%5C1L%3D10%5E3cm%5E3)
Therefore, the volume of a sample of 4.00 mol of copper is ![28.5cm^3](https://tex.z-dn.net/?f=28.5cm%5E3)
Charge= Protons- electrons
Charge= 35p-37e= -2
This Ion will have a charge of -2<span>. </span>
Answer:
When scientists have a question, they form a hypothesis, <em>which</em><em> </em><em>is</em><em> </em><em>an</em><em> </em><em>idea</em><em> </em><em>that</em><em> </em><em>may</em><em> </em><em>be</em><em> </em><em>proved</em><em> </em><em>or</em><em> </em><em>disproved</em><em> </em><em>by</em><em> </em><em>an</em><em> </em><em>experiment</em><em>.</em>
For #5 It's helpful to draw a free body diagram so you know which way the forces are acting on the block.
the weight mg is acting downwards, and you need to find the vertical and horizontal components of mg using sin and cosine. so do 15x9.8xsin40 which is the force. Assuming no friction, this is the only force acting on the block, as the forces on the vertical plane cancel out i.e the normal force and weight of the block.
after, just do F=ma And since you know F and m, solve for a.