Question

What will happen to the 0.1 N force if one charges is increased by a factor of 3?

Answer 1

Answer:

Explanation:

Force between two charges is given by the following expression

F = $\frac{KQ_1Q_2}{d^2}$  Q₁ and Q₂ are two charges and d is distance between two.

.1 = $\frac{KQ_1Q_2}{d^2}$

If Q₁ becomes three times , force will become 3 times . Hence force becomes .3 N in the first case.

Force F = .3 N

If charge becomes one fourth , force also becomes one fourth .

F= $\frac{.1}{4}$

= .025 N.