Remainder of 6099 Divided by 7? The quotient (integer division) of 6099/7 equals 871; the remainder (“left over”) is 2.
37.5
9/24=0.375
Move the decimal two places and you get 37.5%
Splitting up the interval of integration into 
subintervals gives the partition
![\left[0,\dfrac1n\right],\left[\dfrac1n,\dfrac2n\right],\ldots,\left[\dfrac{n-1}n,1\right]](https://tex.z-dn.net/?f=%5Cleft%5B0%2C%5Cdfrac1n%5Cright%5D%2C%5Cleft%5B%5Cdfrac1n%2C%5Cdfrac2n%5Cright%5D%2C%5Cldots%2C%5Cleft%5B%5Cdfrac%7Bn-1%7Dn%2C1%5Cright%5D)
Each subinterval has length 
. The right endpoints of each subinterval follow the sequence
with 
. Then the left-endpoint Riemann sum that approximates the definite integral is
and taking the limit as 
gives the area exactly. We have
2.5 = 2 5/10 as a Mixed fraction
To get a improper fraction, multiply the whole number with the denominator, and then add the numerator to the answer, giving the numerator (keep the denominator number)
2 x 10 = 20
20 + 5 = 25
25/10 is your answer
hope this helps
<span>(7x+3)-(2x+1)
=</span><span>7x + 3 - 2x - 1
= 5x + 2</span>
