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2 years ago

7 11 4 2= 10make it true use the symbols to solve the eqation + ) ( - / x

Mathematics

2 answers:

ArbitrLikvidat [17]2 years ago

8 0

The answer is (7-11)+4+2=10

storchak [24]2 years ago

7 0

Answer:

(7 + 11) - (4 x 2)

Step-by-step explanation:

Adding 7 and 11 gets you to 18

To get to 10 from 18, you need 8

8 can be created by multiplying 4 and 2

Hence, the answer is (7 + 11) - (4 x 2)

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-Chetan K

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Factorise 2p^2 - p - 10<br> (2p squared)

velikii [3]

2p² - p - 10 = 0

2 = a

- 1 = b

- 10 = c

To factor, find two numbers that multiply to equal a·c and also that have a sum of b

2p² + 4p - 5p - 10 = 0

2p (p + 2) - 5 (p + 2) = 0

<h3>Answer: ( 2p - 5 ) ( p + 2 ) = 0</h3>

3 0

2 years ago

Josie bought 750 bags of peanuts for $375 he intends to sell each bag for $.15 more than you paid how much should he charge for

STatiana [176]

Step-by-step explanation:

Jose bought 750 bags for $375.00

Each bag cost $375/750= $0.50

He intends to sells them for $0.15 more

He should charge : $0.5 +$0.15=$0.65

6 0

2 years ago

The floor area of a square room is 225 sq. ft. What is the measure of each side of the room in feet?

I am Lyosha [343]

Answer:

56.25 feet

Step-by-step explanation:

225 divided by 4 is 65.25

8 0

2 years ago

Solve for x. Your answer must be simplified. -3 < x/-4

Harman [31]

Answer:

x<12

Step-by-step explanation:

Let's solve your inequality step-by-step.

−3< x/ −4

Step 1: Simplify both sides of the inequality.

−3< −1/ 4 x

Step 2: Flip the equation.

−1/ 4 x>−3

Step 3: Multiply both sides by 4/(-1).

( 4/ −1 )*( −1/ 4 x)>( 4 /−1 )*(−3)

x<12

Answer:

x<12

4 0

2 years ago

Of interest is to test the hypothesis that the mean length of all face-to-face meetings and the mean length of all Zoom meetings

Goshia [24]

Answer:

Null hypothesis: $\mu_1 = \mu_2 = ..... \mu_j , j =1,2,....,n$

Alternative hypothesis: $\mu_i \neq \mu_j , i,j =1,2,....,n$

The alternative hypothesis for this case is that at least one mean is different from the others.

And the best method for this case is an ANOVA test.

Step-by-step explanation:

For this case we wnat to test if all the mean length of all face-to-face meetings and the mean length of all Zoom meetings are the same. So then the system of hypothesis are:

Null hypothesis: $\mu_1 = \mu_2 = ..... \mu_j , j =1,2,....,n$

Alternative hypothesis: $\mu_i \neq \mu_j , i,j =1,2,....,n$

The alternative hypothesis for this case is that at least one mean is different from the others.

And the best method for this case is an ANOVA test.

6 0

2 years ago