<wxz + <zxy= <wxy
<wxy= 105
105/2= 52.5
52.5 + 52.5 = 105
105 = 105
m<wxz = 52.5
A:93
B: slope
the slope is the rate of change of the line.
this line models the distance between cop and the driver. note that the
cop is standing still while the sports car is moving away at 93 mph
if
the x-axis is in hours and the y-axis is in miles, then slope =
rise/run = km/h, which is kilometers per hour. the slope is the rate of
change of distance for the distance vs time graph
therefore the slope is 93 mph
It would be 45º. Don't question me
<span>0.176 = 176⁄1000</span>
<span>Simplify 176⁄1000 = 22⁄125</span><span> </span>
1. 4x + 2y = 11
x - 2 = -2y
First I would isolate one of the variables (x or y) of one of the equations, and then substitute it into the other equation.
The easiest to isolate is the "x" in the second equation
x - 2 = -2y Add 2 on both sides
x = -2y + 2
Substitute this into the first equation
4x + 2y = 11
4(-2y + 2) + 2y = 11 Multiply 4 into (-2y + 2)
-8y + 8 + 2y = 11 Combine like terms
-6y + 8 = 11 Subtract 8 on both sides
-6y = 3 Divide -6 on both sides
y = -3/6 Simplify
y = -1/2
Now that you know "y", you can plug it into either of the original equations to find "x"
x - 2 = -2y
x - 2 = -2(-1/2)
x - 2 = 1 Add 2 on both sides
x = 3
Answer is A
2. y = 3x + 5
4x - y = 5
Substitute the first equation into the second equation
4x - y = 5
4x - (3x + 5) = 5 Multiply/distribute the - into (3x + 5)
4x - 3x - 5 = 5 Combine like terms
x - 5 = 5 Add 5 on both sides
x = 10
Plug in "x" into either of the original equations to find "y"
y = 3x + 5
y = 3(10) + 5
y = 30 + 5
y = 35
Answer is A
