the Pythagorean Theoremproof of let ΔABC be a right triangle. and sinA=a/c, and cosA= b/ca opposite side of the angle Ab the adjacent side of the angle Aand c is the hypotenuswe know that sin²A +cos²A= (a/c)²+ (b/c) ², but sin²A +cos²A=1so, a²/c²+ b²/c ²=1 which implies a²+ b²=c² the answer is Transitive Property of Equality proof the right triangles BDC and CDA are siWe start with the original right triangle, now denoted ABC, and need only one additional construct - the altitude AD. The triangles ABC, DBA, and DAC are similar which leads to two ratios:AB/BC = BD/AB and AC/BC = DC/AC.Written another way these becomeAB·AB = BD·BC and AC·AC = DC·BCSumming up we getAB·AB + AC·AC= BD·BC + DC·BC = (BD+DC)·BC = BC·BC.so not in the proof is Transitive Property of Equality
X should equal 70 I think.
C will be the y-intercept in the equation which will shift it up and down
Answer : A
Answer:
Step-by-step explanation:
. cubesi, 20,64. AV 1,6,11,16... Add 5. 1, 2, 4, 8. . Multiply 2. $2,9,28,65... cubes add 1. 31,49,16 ...
Answer: choice B
Step-by-step explanation:
The graph of y=-3x^n is the reflection of the graph of y=3x^n about the x-axis.
