To find equivalent inequalities you have to work the inequality given.
The first step is transpose on of sides to have an expression in one side and zero in the other side:
x - 6 x + 7
--------- ≥ --------
x + 5 x + 3
=>
x - 6 x + 7
--------- - -------- ≥ 0
x + 5 x + 3
=>
(x - 6) (x + 3) - (x + 7) (x + 5)
--------------------------------------- ≥ 0
(x + 5) (x + 3)
=>
x^2 - 3x - 18 - x^2 - 12x - 35
--------------------------------------- ≥ 0
(x + 5) (x + 3)
15x + 53
- ------------------- ≥ 0
(x + 5) (x + 3)
That is an equivalent inequality. Sure you can arrange it to find many other equivalent inequalities. That is why you should include the list of choices. Anyway from this point it should be pretty straigth to arrange the terms until making the equivalent as per the options.
Okay, let's add the two x values.
10x + 75 = 5x = 110
15x + 75 = 110
Now let's minus 75 from each side.
15x = 35
Now let's divide each side by 15.
x = 2.333333333
The value of x in the equation 4(x + 5) = 9x + 4x − 34 is 6 after solving and applying properties.
<h3>What is a linear equation?</h3>
It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.
We have equation:
4(x + 5) = 9x + 4x − 34 (Given)
4x +20 = 9x + 4x − 34 (Distributive Property)
4x +20 +34 -4x = 9x + 4x − 34 + 34 -4x (Subtraction Property of Equality)
54 = 9x + 4x − 34 + 34 -4x (Addition Property of Equality)
54 = 9x (Combine Like Terms)
x = 54/9 (Division Property of Equality)
x = 6
Thus, the value of x in the equation 4(x + 5) = 9x + 4x − 34 is 6 after solving and applying properties.
Learn more about the linear equation here:
brainly.com/question/11897796
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Answer:
x=36
y=6
Step-by-step explanation:
Let the numbers be x and y
Condition 1
x=6y ----------(1)
Condition 2
x-y=30 ------------(2)
Putting 1 in 2
6y-y=30
5y=30
Dividing both sides by 5
y=6
Now
Putting y=6 in 1
We get
x=6(6)
x=36
Answer:
a.) one sample t test
b.) H0 : μ = 59.3
c.) H1 : μ > 59.3
d.) μ = 59.3 ; σ = 39.84
e.) xbar = 79.4 ; s = 61.36
Test statistic = 3.16
Step-by-step explanation:
Given the sample data:
49.00 49.00 49.00 49.00 49.00 63.00 63.00 63.00 63.00 63.00 199.00 199.00 199.00 199.00 199.00 38.00 38.00 38.00 38.00 38.00 48.00 48.00 48.00 48.00 48.00 49.00 63.00 199.00 38.00 48.00
Sample size, n = 30
Using calculator :
xbar from the data above = 79.4
Standard deviation = 61.359
H0 : μ = 59.3
H1 : μ > 59.3
Test statistic :
(Xbar - μ) ÷ (σ/sqrt(n)
σ = 34.83
(79.4 - 59.3) ÷ (34.83/sqrt(30))
20.1 ÷ 6.359
Test statistic = 3.16