Let the shorter diagonal be x, then
x^2 = 6^2 + 10^2 - 2 x 6 x 10 x cos 70 = 36 + 100 - 120 cos 70 = 136 - 41.04 = 94.96
x = sqrt(94.96) = 9.7 cm
The other angle of the parallelogram is 1/2(360 - 2(70)) = 1/2(360 - 140) = 1/2(220) = 110
Let the longer diagonal be y, then
y^2 = 6^2 + 10^2 - 2 x 6 x 10 x cos 110 = 36 + 100 - 120 cos 110 = 136 + 41.04 = 177.04
y = sqrt(177.04) = 13.3 cm.
Therefore, the length of the diagonals are 9.7 cm and 13.3 cm.
Answer:
the coordinates of C' = (2,1)
Step-by-step explanation:
The coordinates of point C can be found by looking at the graph.
Coordinates of C are C= (6,3)
If ABCD is dilated by a factor of 1/3 then the coordinates of C' can be found by multiplying the coordinates of C by 1/3
C = (6,3)
C' =(1/3*6,1/3*3)
C' = (2,1)
So, the coordinates of C' = (2,1)
The slope of the line is calculated using
y2 - y1 / x2 - x1
Substituting the given values
-8 - 27 / 5 - 0 = -7
The rate of change or the slope is -7
And the initial value is the value of y when x is 0. From the first coordinates, the initial value is 27.
Answer:
Option A
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The perimeter = 2 length + 2 width
the length = the width +47
314 = 2*(w+47) +2w
314 = 2w +94 +2w
220 =4w
w= 220/4 = 55
l = 55+47 = 102
the length = 102 ft
the width = 55 ft
hope helped
