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3 years ago

Answer these two and show work please ! :)

Mathematics

1 answer:

SashulF [63]3 years ago

3 0

Answer:

8. $\frac{4x}{x^{2} -1}$

10. $\frac{1-2xy}{3x^{2} }$

Step-by-step explanation:

8. write all numerators above the least common denominator, that is going to look like x/x+1/x+1-2/4. next we calculate the difference on the third level of the fraction, where it is x+1-2. we end up getting x/x+1/x-1/4. now we need to simplfy the fraction. that will be 4x/(x+1)*(x-1). now we simplfy the product on the denominator so it is going to be 4x/x^2-1.

10. we reduce the fraction on the left with 2. that is going to turn the left side of the fraction from 2x/6x^3 into x/3x^3. now our expression is x/3x^2 - 4y/6x. now we simplify the expression into 1/3x^2 - 4y/6x. now we reduce the fraction on the right side with 2. that is going to turn 4y/6x into 2y/3x. now we have the expression 1/3x^2 - 2y/3x. we now write all numerators above the least common denominator 3x^2. that is going to then look like 1-2xy/3x^2 which is our answer.

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If XX is a binomial random variable, compute the mean, the standard deviation, and the variance for each of the following cases:

Liula [17]

Answer:

(a) The mean, variance and standard deviation of X are 1.60, 0.96 and 0.98 respectively.

(b) The mean, variance and standard deviation of X are 3.20, 0.64 and 0.80 respectively.

(d) The mean, variance and standard deviation of X are 4.00, 0.80 and 0.89 respectively.

Step-by-step explanation:

The random variable X follows a Binomial distribution with parameters n and p.

The mean, variance and standard deviation of X are:

$\mu=np\\\sigma^{2}=np(1-p)\\\sigma=\sqrt{np(1-p)}$

(a)

For n = 4 and p = 0.40 compute the mean, variance and standard deviation of X as follows:

$\mu=np=4\times0.40=1.60\\\sigma^{2}=np(1-p)=4\times0.40\times(1-0.40)=0.96\\\sigma=\sqrt{np(1-p)}=\sqrt{0.96}=0.98$

Thus, the mean, variance and standard deviation of X are 1.60, 0.96 and 0.98 respectively.

(b)

For n = 4 and p = 0.80 compute the mean, variance and standard deviation of X as follows:

$\mu=np=4\times0.80=3.20\\\sigma^{2}=np(1-p)=4\times0.80\times(1-0.80)=0.64\\\sigma=\sqrt{np(1-p)}=\sqrt{0.64}=0.80$

Thus, the mean, variance and standard deviation of X are 3.20, 0.64 and 0.80 respectively.

(c)

For n = 3 and p = 0.50 compute the mean, variance and standard deviation of X as follows:

$\mu=np=3\times0.50=1.50\\\sigma^{2}=np(1-p)=3\times0.50\times(1-0.50)=0.75\\\sigma=\sqrt{np(1-p)}=\sqrt{0.75}=0.87$

Thus, the mean, variance and standard deviation of X are 1.50, 0.75 and 0.87 respectively.

(d)

For n = 5 and p = 0.80 compute the mean, variance and standard deviation of X as follows:

$\mu=np=5\times0.80=4.00\\\sigma^{2}=np(1-p)=5\times0.80\times(1-0.80)=0.80\\\sigma=\sqrt{np(1-p)}=\sqrt{0.80}=0.89$

Thus, the mean, variance and standard deviation of X are 4.00, 0.80 and 0.89 respectively.

6 0

3 years ago

Harry has three vehicles (bicycle,scooter, and car). He uses them to go to school, the garden, and the theatre. If he is out of

tamaranim1 [39]

He could be using either his bicycle, scooter, and the car. He could also be at either the school, garden or theatre. There are 3 possible methods of his transportation and places he could be. So Your Answer is 3.

7 0

3 years ago

Plz I need this thank you this is for 100 points luv u

Verizon [17]

Answer:

a. 120

b. -120

c. -120

d. -120

e. 120

Step-by-step explanation:

The amount of - will influence whether the value is positive or negative. Odd number of - is always negative. Even number of - is always positive. Hope this helped :)

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4 years ago

HELP ME PLSSSSSSS!!!!!!!!!

goblinko [34]

Domain of the function

4 0

3 years ago

What is 6/10 as hundredths in fraction form

Step2247 [10]

To get in hundredths form you need to multiply both the numerator and denominator by 10. 6×10=60 and 10×10=100
The answer is 60/100

7 0

3 years ago