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SVETLANKA909090 [29]
4 years ago
10

Solve for n : 21k 3n + 9p >3p+12

Mathematics
1 answer:
pickupchik [31]4 years ago
7 0

Answer:

n>\frac{-6p+12}{63k}

Step-by-step explanation:

21k3n>3p-9p+12

21k3n>-6p+12

3n>\frac{-6p+12}{21k}

n>\frac{-6p+12}{63k}

Are you sure you typed the question correctly? like is there supposed to be something between the 21k and the 3n?

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