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tekilochka [14]
3 years ago
9

BRAINLIEST!!!!!!!!

Mathematics
2 answers:
alexandr402 [8]3 years ago
5 0

Answer:

Sample Response: Locate two corresponding ordered pairs of the two shapes. Calculate how much the pre-image values were multiplied by to obtain the image values. This is your scale factor. You can calculate this by dividing the coordinates of the mage by the corresponding coordinates of the pre-image.

hope i helped

polet [3.4K]3 years ago
4 0

The shapes are similar, there was a dilation, which is what made the shape either bigger or smaller. I am not very good with instructions, but I will try to answer my best. You could set up a ratio, Bigger shape/smaller shape, or vice versa.  Wish I could have helped more, sorry.


Good Luck! Hope I helped:)


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The sum of 2 times a number and 8 is 7
My name is Ann [436]

Answer:

The number is -1/2

Step-by-step explanation:

Let x be the number

2x+8 = 7

Subtract 8 from each side

2x+8-8 = 7-8

2x = -1

Divide each side by 2

2x/2 =-1/2

x = -1/2

The number is -1/2

8 0
3 years ago
Read 2 more answers
The table above represents what type of function?
exis [7]

Answer:

A?? because I think it's not linear because it's not proportional

7 0
3 years ago
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I really need help and reallly fassttttttt
Vikki [24]

Answer:

1:    1.06c−10

2:    0.048c−9.2

3:    0.8c(1.06)

Step-by-step explanation:

Brainliest pleasee

7 0
3 years ago
Find the least common multiple for 6(x+1)^3(x-4)^2 and 10(x+1)^8(x-4)^5
dolphi86 [110]

Answer:

30(x+1)^8 (x-4)^5

Step-by-step explanation

<h3>6(x+1)^{3}(x-4))^{2}=2X3 X (x+1)^3(x-4)^2\\10(x+1)^8(x-4)^5)= 2X5X(x+1)^8 (x-4)^5\\</h3>

In order to find the Least common multiple we write each of the factor only once from each of the expression and for the common expression we take their LCM as maximum of the exponent in  all expressions

as here in the question exponent of (x+1) are 3 and 8 so we take exponent 8

likewise for (x-4) we shall take maximum of 2 and 5 which is 5

so our expression for Least common multiple will be

2X3X5 X (x+1)^8 (x-4)^5

30(x+1)^8 (x-4)^5

7 0
3 years ago
3(x + 4) + 2 = 2 + 5(x – 4) what is the fifth step in solving this equation.
kotegsom [21]
3(x+4)+2= 2+5(x-4)

3x+12+2= 2+ 5x-20

3x+14= 5x-18

3x+14-14= 5x-18-14

3x= 5x-32

3x-5x = 5x-32-5x

-2x= -32

-2x/ -2= -32/-2

x= 16

So answer A combine
8 0
3 years ago
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