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3 years ago

What is the area of this figure?

Mathematics

1 answer:

Alexxandr [17]3 years ago

5 0

Answer:

The area of the figure is equal to $35\ cm^{2}$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The area of the figure is equal to the area of a square plus the area of a triangle

Find the area of the square

The area of square is equal to

$A=b^{2} =5^{2}=25\ cm^{2}$

Find the area of the triangle

The area of the triangle is equal to

$A=(1/2)bh=(1/2)(5)(4)=10\ cm^{2}$

therefore

The area of the figure is equal to

$25\ cm^{2}+10\ cm^{2}=35\ cm^{2}$

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Is the point 3/5 and 4/5 corresponds to an angle in the unit circle what is the csc

Mariulka [41]

Answer:

csc = 5/4

Step-by-step explanation:

Assuming that the two given points 3/5 and 4/5 are the two sides of a triangle and a right angle 0 with legs x and y and z as its hypotenuse.

Then using Pythagoras Theorem:

$z^2=x^2+y^2$

$z^2=(\frac{3}{5} )^2+(\frac{4}{5} )^2$

$z^2 = \frac{9}{25} + \frac{16}{25}$

$z^2=\frac{25}{25}$

$z^2=1$

Taking square root on both the sides:

$z=1$

Now, $sin\alpha=\frac{4}{5}$

and we know that $csc = \frac{1}{sin\alpha }$

Therefore, csc = 5/4.

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