Answer:
D: y = 3x² - 5x - 2
Step-by-step explanation:
The general form of a quadratic equation is: y = ax² + bx + c
c is the y-intercept
We are given the point (0, -2) which is the y-intercept, so we can rewrite our general form into
y = ax² + bx - 2
We can create a system of equations to solve for a and b. We are given two points.
Equation 1: Take the first point (-2, 20) and plug it into our general equation...
20 = a(-2)² + b(-2) - 2
20 = 4a - 2b - 2
22 = 4a - 2b (add 2 to both sides)
11 = 2a - b (divide both sides by 2 since every coefficient is even)
Equation 2: Take the point (1, -4) and plug it into the general equation
-4 = a(1)² + b(1) - 2
-4 = a + b - 2
-2 = a + b
Now we have our 2 equations:
11 = 2a - b
-2 = a + b
Since the coefficients of b are already have opposite signs, add the two equations together (elimination method)
Now we have
9 = 3a now solve for a...
3 = a (divide by 3 on both sides)
If a = 3, then
-2 = 3 + b
-5 = b
Our equation is
y = 3x² - 5x - 2
Y=8/11x has the unit rate greater than that function shown in graph.
Answer:
B.) f(x) = 3(4)x − 1
Step-by-step explanation:
A) f(x) = 12(4)x
B.) f(x) = 3(4)x − 1
C.) f(x) = 4(12)x
D.) f(x) = 4(3)x − 1
Given:
f(x+1) = 4f(x)
f(2)=12
f(2) = 12
f(3) = 4f(2) = 4 * 12 = 48
f(3)=48 and f(2)=12
From f(3)=48 and f(2)=12
r=48/12
=4
r=common ratio
Recall,
f(2)=12=ar
r=4
f(2)=ar=12
a*4=12
a=12/4
a=3
an=ar^(n-1)
For x term
an=3*4(x-1)
B.) f(x) = 3(4)x − 1
Answer:
a)30-1,2,3,5,6,10,15,30
b)20-1,2,4,5,10,20
Step-by-step explanation:
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Answer:
Step-by-step explanation:
On a normal distribution table with z scores of 0 as the mean and the standard deviations going to the right and to the left, 1.9 on the normal curve where 3 is the mean falls at -.275 on the normal curve where 0 is the mean. I used the normal distribution z table for negative values to get that .39165 lies to the left of -.275, which means that 1 - .39165 of the data lies to the right.
The probability that the value is greater than 1.9 is .60835, or as a percentage, 60.835%.
