Answer:
0.70275
Step-by-step explanation:
Data provided in the question:
4e²ˣ⁻¹ -1 = 5
now solving for 'x'
⇒ 4e²ˣ⁻¹ = 5 + 1
or
⇒ 4e²ˣ⁻¹ = 6
or
⇒
or
⇒
now,
taking natural log both sides, we get
⇒ 2x - 1 =
also,
we know
⇒
thus,
⇒ 2x - 1 = ln(3) - ln(2)
or
⇒ 2x - 1 = 1.0986 - 0.6931
or
⇒ 2x - 1 = 0.4055
or
⇒ 2x = 0.4055 + 1
or
⇒ 2x = 1.4055
or
⇒ x = 0.70275
<u>Answer-</u>
<em>The correct answer is</em>
<em>∠BDC and ∠AED are right angles</em>
<u>Solution-</u>
In the ΔCEA and ΔCDB,
As this common to both of the triangle.
If ∠BDC and ∠AED are right angles, then
Now as
∠BCD = ∠ACE and ∠BDC = ∠AED,
∠DBC and ∠EAC will be same. (as sum of 3 angles in a triangle is 180°)
Then, ΔCEA ≈ ΔCDB
Therefore, additional information can be used to prove ΔCEA ≈ ΔCDB is ∠BDC and ∠AED are right angles.
