Answer:
The description of the given code is given below:
Explanation:
Memory leak:
In a program, if memory is assigned to the pointer variables but that memory is already released previously then the condition of occurring the memory leakage.
Now the program :
#include <stdio.h> //header file
#include <stdlib.h> //header file
#include <string.h> //header file
int main() //main function
{
char *word1 = NULL; //line 1 (as given in the question)
word1 = malloc(sizeof(char) * 11); //line 2
free(word1); //free the memory of pointer word1 line 3
word1 = "bramble"; //line 4
char *word2 = NULL; //line 5
word2 = malloc(sizeof(char) * 11); //line 6
free(word2); //free the memory of pointer word2 line 7
word2 = word1; //line 8
return 0; //line 9
}
Therefore, line 3 is the first line that introduce a memory leak anf after that line 7 introduce it in a program.
