Question

The range of which function is (2, infinity)? y = 2x y = 2(5x) y = 5x +2 y = 5x + 2

Answer 1

Answer:

y = 5∧× + 2

Step-by-step explanation:

Answer 2

Answer:

I think your functions are $y=2^{x}$ ,$y=2*5^{x}$ and $y=2+5^{x}$

If yes then then the third function which is $y=2+5^{x}$.

Step-by-step explanation:

The function $c^{x}$ where c is a constant has

Domain : $c\geq 0$

Range : ( 0 , ∞ )

The above range is irrespective of the value of c.

I have attached the graph of each of the function, you can look at it for visualization.

• $y=2^{x}$ ⇒ This function is same as  $c^{x}$ so its range is ( 0 , ∞ ).

• $y=2*5^{x}$ ⇒ If we double each value of the function $y=5^{x}$, which has range ( 0 , ∞ ), but still the value of extremes won't change as 0*2=0 and ∞*2=∞. Therefore the range remains as ( 0 , ∞ ).

• $y=2+5^{x}$ ⇒ If we add 2 to each value of the function $y=5^{x}$, which has range ( 0 , ∞ ), the lower limit will change as 0+2=2 but the upper limit will be same as ∞. Therefore the range will become as ( 2 , ∞ ).