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2 years ago

Fill in the missing numbersI need an answer ASAP

Mathematics

1 answer:

mamaluj [8]2 years ago

4 0

Answer:

the missing numbers be 60 and 6 respectively

Step-by-step explanation:

The computation of the missing numbers are shown below:

Let us assume the missing numbers be x

, $\frac{1}{2} \times 30 = \frac{1}{4} \times x\\\\15 = \frac{1}{4} \times x\\\\x = 60$

$\frac{1}{3} \times 12 = \frac{2}{3} \times x\\\\4 = \frac{2}{3} \times x\\\\x = 6$

Hence, the missing numbers be 60 and 6 respectively

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The daily profit P (in thousands of dollars) from the sale of televisions is a function of the number x of televisions sold (

scZoUnD [109]

Answer:

The break-even sales amounts is 36 or 224.

Step-by-step explanation:

Consider the provided function.

$P= -5x^2 + 13x - 4$

Where x is the number of televisions sold (in hundreds) and P is the profit.

We need to calculate the break-even sales amounts.

the break-even sales amounts is the sales amounts that result in no profit or loss.

That means substitute P=0 and solve for x.

$-5x^2 + 13x - 4=0$

$5x^2-13x+4=0$

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Substitute a=4, b=-13 and c=4 in above formula.

$x_{1,\:2}=\frac{-\left(-13\right)\pm \sqrt{\left(-13\right)^2-4\cdot \:5\cdot \:4}}{2\cdot \:5}$

$x_{1,\:2}=\frac{13\pm\sqrt{169-80}}{10}$

$x_{1,\:2}=\frac{13\pm\sqrt{89}}{10}$

$x=\frac{13+\sqrt{89}}{10},\:x=\frac{13-\sqrt{89}}{10}\\x\approx2.243, \ or\ x\approx 0.357$

Therefore, the break-even sales amounts is 36 or 224.

7 0

2 years ago

Translate the algebraic expression below into a written expression.

tensa zangetsu [6.8K]

Answer:

Its C

Step-by-step explanation:

6 0

2 years ago

A large adult kangaroo can have a mass of 90,000 grams. How many kilograms is it. (1g =1,000g)

liubo4ka [24]

$1kg=1,000g!!!\\\\therefore\ 1g=\frac{1}{1,000}kg=0.001kg\\--------------------\\90,000g=90,000\cdot0.001kg=\boxed{90kg}\\\\Answer:\boxed{\boxed{90,000g=90kg}}$

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2 years ago

Read 2 more answers

Question Which of these strategies would eliminate a variable in the system of equations? 2x - y = 11 5x + 3y = -11 How many pos

kenny6666 [7]

Answer:

Elimination (multiplication and subtraction)

There is 1 solution

Step-by-step explanation:

The only way to solve this system of equations is by elimination (multiplication). Let's say that we want to cancel out the x. You multiply the first equation by 5 and you multiply the second equation by 2.

Your equations now are:

10x-5y=55 and 10x+6y=-22

You can subtract these equations to get -11y = 77.

Now that we know that y = -7, we can substitute y in to solve x.

10x-5(-7) = 55

10x=20

x=2

Final answer (2,-7)

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2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Chuge%7B%5Cgreen%7D%5Cfcolorbox%7Bblue%7D%7Bcyan%7D%7B%5Cbf%7B%5Cunderline%7B%5Cred%7B%5C

MariettaO [177]

$\qquad\qquad\huge\underline{{\sf Answer}}$

Let's find out the gradient (Slope " m ") of line q ;

$\qquad \sf \dashrightarrow \:m = \dfrac{y_2 - y_1}{x_2 - x_1}$

$\qquad \sf \dashrightarrow \:m = \dfrac{4 - 0}{0 - 1}$

$\qquad \sf \dashrightarrow \:m = - 4$

Now, since we already know the gradient let's find of the equation of line by using its Slope and one of the points using point slope form of line :

$\qquad \sf \dashrightarrow \:y - 4 = m(x - 0)$

$\qquad \sf \dashrightarrow \:y = mx + 4$

Now, plug in the value of gradient ~

$\qquad \sf \dashrightarrow \:y = - 4x + 4$

here we can clearly observe that, the Area under the curve can easily be represented as :

$\qquad \sf \dashrightarrow \:y < - 4x + 4$

Since, all the values of y that lies in the shaded region is smaller than the actual value of y for the corresponding values of x in the equation of line q

5 0

1 year ago

Fill in the missing numbersI need an answer ASAP​

Fill in the missing numbersI need an answer ASAP