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Paha777 [63]
2 years ago
7

Point P please help i appreciate whoever does (:

Mathematics
1 answer:
In-s [12.5K]2 years ago
6 0

Answer:

  y = (√7)/4

Step-by-step explanation:

The equation of the unit circle is ...

  x^2 +y^2 = 1

Putting the given value in for x, we can find y to be ...

  (-3/4)^2 +y^2 = 1

  y^2 = 1 -(-3/4)^2 = 1 -9/16 = 7/16 . . . . . subtract 9/16

  y = √(7/16) . . . . . . . . . . . take the square root; y > 0 here

  y = (√7)/4

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WHAT WOULD THIS BEEEEEEE!!!!
kaheart [24]

Answer:

X=35°

Y=70°

Z=110°

I think this ans may help you

4 0
3 years ago
Read 2 more answers
How to solve pythagorean theorem i need an assay someone help
Veronika [31]

Answer:

first write the formula

Step-by-step explanation:

Hypotenuse^2 = Perpendicular ^2 + Base^2

only applicable for a right triangle (one of the sides is of measure 90 degree

Give an example

let is assume in Triangle ABC, angle B = 90 degrees

AB = 3cm

BC = 4 cm

to find AC or hypotenuse

Solution

by using pythagoras formula we get

(AB)^2 + (BC)^2 = (AC)^2

(3)^2 + (4)^2 = (AC) ^2

9 + 16 = (AC)^2

25 = (AC)^2

Root of 25 = AC

5cm =AC

Write about how pythagoras theorem was formed

mathematician who derived it

in which year

Application of Pythagorean theorem

Pythagorean Triplets etc.

I think this willbe enough for an essay

GOOD LUCK FOR THE FUTURE! :)

5 0
3 years ago
The function y= 5^x passes through the point
wlad13 [49]
The correct answer is c :)
the point is described by two variables: x and y. it is written like that: (x, y). so the first variable in brackets is the x variable. the other is y. so pick every point a-d, put these values into the equation, solve it and check if the values before and after = are the same. if so - you are correct!
look:
c) (1, 5) so x=1, y=5
equation: y=5^x
putting values: 5=5^1 and this is true!
4 0
3 years ago
if a right triangle has lengths 99 inches, 101 inches and 20 inches, what is the length of the hypotenuse
Anna35 [415]

Answer:

The hypotenuse is 10201

Step-by-step explanation:

20^2+99^2=101^2

400+9801=10201

10201=10201

5 0
2 years ago
Can anyone plzzzz help me with this question of linear equation in two varaiable plzzzzzz... Its very important... Plz solve it
kotegsom [21]

That's not a linear system, but you have an awesome school system for giving you this problem.

\dfrac 5 y - \dfrac 2 x = \dfrac{13}6

Multiply by 6xy to clear the fractions.

30x - 12y = 13 xy

That's a second degree equation, also known as a conic.  That one happens to be a hyperbola.  

30x = y(13 x +12)

y = \dfrac{30x}{13 x + 12}

Let's clear the fractions from the second equation, multiplying out common denominator xy:

\dfrac {36} x - \dfrac {24} y = 1

36y - 24 x = xy

We are being asked to find the meet of two hyperbolas, so we expect two answers, a quadratic equation.

Substituting,

36 \left( \dfrac{30x}{13 x + 12} \right) - 24 x = x \left( \dfrac{30x}{13 x + 12} \right)

36(30x) -24 x(13x + 12) = 30x^2

1080 x - 312 x^2- 288 x = 30x^2

x(792 - 342 x)= 0

x = 0 \textrm{ or } x=792/342 = \dfrac{44}{19}

We have to rule out x=0 because it's in the denominator.

y = \dfrac{30x}{13 x + 12} = \dfrac{30(44/19)}{13(44/19)+12}

y = \dfrac{33}{20}

Answer: (44/19, 33/20)

8 0
3 years ago
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