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Ulleksa [173]
3 years ago
6

X^2 + 4y^2 =100; 4y - x^2 = -20

Mathematics
1 answer:
deff fn [24]3 years ago
7 0
x^2+4y^2=100\implies x^2=100-4y^2
\implies 4y-(100-4y^2)=-20
\implies 4y^2+4y-80=0
\implies y^2+y-20=0
\implies (y-4)(y+5)=0
\implies y=4,y=-5

When y=4, you have

4(4)-x^2=-20\implies x^2=36\implies x=\pm6

When y=-5,

4(-5)-x^2=-20\implies x^2=0\implies x=0

So there are three solutions, (x,y)\in\{(6,4),(-6,4),(0,-5)\}.
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Answer:

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Step-by-step explanation:

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Sample space= S= {1, 2, 3, 4, 5, 6}

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3 years ago
Expand.<br> If necessary, combine like terms.<br> (x+5)(x-5)=(x+5)(x−5)=
AlekseyPX

Answer:

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Step-by-step explanation:

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