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3 years ago

Katie has read 32% of a book. if she has read 80 pages, how many more pages does Katie have left to read?

1 answer:

5 0

Katie has read 32%, so 32%=80 pages. To get the total number of pages, you have to divide 32 and 80 by 8 to get 4% and 10 pages. 4% of the book is 10 pages, and in order to get 100%, you have to multiply by 25(4*25=100) on both sides. Remember, what you do to one side, you do to the other side. That leaves you with 100% and 250 pages. The book is 250 pages long. If she has read 80 pages, you subtract 80 from 250 to find how many pages she has left to read. The difference is 170. Katie has 170 pages left to read.

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How do you find degree measures? How would you solve this question?

MrRa [10]

A. a=145 b=35 c=145 d=145 e=35 f=145 g=35

b. These are the pairs of vertical angles: a & c, b & 35, d & f, e & g.

Hope this was helpful.

8 0

2 years ago

Find the area of the circle below???

olga55 [171]

Answer:

Area of the circle = $24.618\,feet^2$

Step-by-step explanation:

Radius of the circle= $2.8\,feet$

Area of the circle= $\pi \times r^2$

As,

$\pi =\dfrac{22}{7} =3.14$

Area of the circle is:

$=3.14\times 2.8 \times 2.8\\\\= 3.14 \times 7.84\\\\=24.618\,feet^2$

The Area of the circle is : $24.618\,feet^2$

5 0

2 years ago

Read 2 more answers

Solve the equation on the interval [0,2π]

WARRIOR [948]

$\bf 16sin^5(x)+2sin(x)=12sin^3(x)
\\\\\\
16sin^5(x)+2sin(x)-12sin^3(x)=0
\\\\\\
\stackrel{common~factor}{2sin(x)}[8sin^4(x)+1-6sin^2(x)]=0\\\\
-------------------------------\\\\
2sin(x)=0\implies sin(x)=0\implies \measuredangle x=sin^{-1}(0)\implies \measuredangle x=
\begin{cases}
0\\
\pi \\
2\pi 
\end{cases}\\\\
-------------------------------$

$\bf 8sin^4(x)+1-6sin^2(x)=0\implies 8sin^4(x)-6sin^2(x)+1=0$

now, this is a quadratic equation, but the roots do not come out as integers, however it does have them, the discriminant, b² - 4ac, is positive, so it has 2 roots, so we'll plug it in the quadratic formula,

$\bf 8sin^4(x)-6sin^2(x)+1=0\implies 8[~[sin(x)]^2~]^2-6[sin(x)]^2+1=0
\\\\\\
~~~~~~~~~~~~\textit{quadratic formula}
\\\\
\begin{array}{lcccl}
& 8 sin^4& -6 sin^2(x)& +1\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array} 
\qquad \qquad 
sin(x)= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}
\\\\\\
sin(x)=\cfrac{-(-6)\pm\sqrt{(-6)^2-4(8)(1)}}{2(8)}\implies sin(x)=\cfrac{6\pm\sqrt{4}}{16}
\\\\\\
sin(x)=\cfrac{6\pm 2}{16}\implies sin(x)=
\begin{cases}
\frac{1}{2}\\\\
\frac{1}{4}
\end{cases}$

$\bf \measuredangle x=
\begin{cases}
sin^{-1}\left( \frac{1}{2} \right)
sin^{-1}\left( \frac{1}{4} \right)
\end{cases}\implies \measuredangle x=
\begin{cases}
\frac{\pi }{6}~,~\frac{5\pi }{6}\\
----------\\
\approx~0.252680~radians\\
\qquad or\\
\approx~14.47751~de grees\\
----------\\
\pi -0.252680\\
\approx 2.88891~radians\\
\qquad or\\
180-14.47751\\
\approx 165.52249~de grees
\end{cases}$

3 0

3 years ago

A biased coin is tossed 40 times. Out of those 40 tosses, the coin landed on heads 12 times.

Ierofanga [76]

Answer:

Step-by-step explanation:The probability of picking the biased coin: P(biased coin)=1/100. The probability of all three tosses is heads: P(three heads)=1×1+99×18100. The probability of three heads given the biased coin is trivial: P(three heads|biased coin)=1.

7 0

2 years ago

How do you write 600,000,000,000 40,000,000 9,000,000 50,000 8,000 100, 2 in standard form?

Likurg_2 [28]

Count the number of 0

1. 6×10^11
2. 4×10^7
3. 9×10^6
4. 5×10^4
5. 8×10^3
6. 1×10^2
7. 2

6 0

2 years ago