Answer:MAFS.912.A-CED.1.1
The measures of three sides of a triangle can be represented by 2x, 3x - 5, and 4x + 2.
The perimeter of the triangle is 65 inches.
a) Give an equation to represent this situation.
b) Solve for x.
c) What are the three lengths of the triangle?
Answer:
12, 45, 1.8, -9, 18
Step-by-step explanation:
up up down down left right left right b a start
The uncertainty in x is the horizontal width of the rectangular marker, which is 0.05 mm.
The uncertainty in y is the height of the rectangular marker, which is 0.1 g.
None of thouse answers are corect
but if i was u i would pick d
Answer:
Step-by-step explanation:
2) a) You have to find the area of semicircle.
r = d/2 = 12/2 = 6 mm
Area of semicircle = ![\frac{1}{2}\pi r^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Cpi%20r%5E%7B2%7D)
![= \frac{1}{2}*3.14*6*6\\\\= 3.14*3*6\\\\= 56.52 mm^{2}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B1%7D%7B2%7D%2A3.14%2A6%2A6%5C%5C%5C%5C%3D%203.14%2A3%2A6%5C%5C%5C%5C%3D%20%2056.52%20mm%5E%7B2%7D)
b) r = 10 cm
Area of quadrant = ![\frac{1}{4}\pi r^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D%5Cpi%20r%5E%7B2%7D)
![= \frac{1}{4}*3.14*10*10\\\\=3.14*5*5\\\\= 78.5 cm^{2}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B1%7D%7B4%7D%2A3.14%2A10%2A10%5C%5C%5C%5C%3D3.14%2A5%2A5%5C%5C%5C%5C%3D%2078.5%20cm%5E%7B2%7D)
3) d = 10 m
r = d/2 = 10/2 = 5 m
Area of circular garden = πr²
= 3.14 * 5 * 5
= 78.5 m²
Area of rectangular pool = 8 * 6 = 48 m²
Area of the garden covered in grass = area of the circular garden - area of pool
= 78.5 - 48
= 30.5 m²
4) a) r = 60 cm
Area of the top of the circular table = πr²
= 3.14 * 60 * 60
= 11304 cm²
diameter of base = 30 cm
r = 30/2 = 15 cm
Area of circular base = 3.14 * 15 * 15
= 706.5 cm²