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Urgent needs an answer now!!!!!!!!!!!!!!!!!!!! Why does it take several redox reactions in a cell to make water from hydrogen an

ycow [4]

Answer:

hydrogen and oxygen combine explosively in a single raction

Explanation:

The reason is Molecules of hydrogen react with oxygen violently to break the initial molecular bonds and form new one between the atoms of the two elements. The reaction results into an explosive release of energy and the production of water because the products of the reaction are at a lower energy level

5 0

3 years ago

Which gene may play a role in patterning the forelimb?

LUCKY_DIMON [66]

Answer: Posterior HoxA and HoxD genes play important roles in patterning along the proximodistal axis of the forelimb (10–13). They also are required for activating and maintaining Shh expression in the developing forelimb (6, 7). mark brainliest

Explanation:

3 0

3 years ago

List two species that may be threatened by the construction of a solar power tower

DENIUS [597]

Answer: the question is incomplete,below is the complete question.

List two species that may be threatened by the construction of a solar power tower in the California Desert

The answers are, Desert torties, mountain yellow legged frog and Joshua tree.

Construction of a solar power tower in the California Desert will threaten the existence of Desert torties, mountain yellow legged frog and and Joshua tree.

Explanation: The construction of solar power towers in Mojave desert in California poses a threat to the existence of quite a number of plants.The Mojave desert houses the largest solar power plant in the world,creating the solar power tower will create job opportunities for people but at the same time endangering the existence of about 12 rare plants that are found in the region of which Desert torties, mountain yellow legged frog and Joshua tree are greatly included,these plants cannot co-exist with solar thermal mirror arrays,this brings a controversy between energy/electricity generation and wildlife/ecosystem conservation.

3 0

3 years ago

4) A homozygous groucho fly ( gro, bristles clumped above the eyes) is crossed with a homozygous rough fly (ro, eye abnormality)

docker41 [41]

Answer and Explanation:

A homozygous groucho fly ( gro, bristles clumped above the eyes) is crossed with a homozygous rough fly (ro, eye abnormality).

The F1 females are testcrossed, producing these offspring: groucho 518 rough 471 groucho, rough 6 wild-type 5 1000 a) What is the linkage distance between the two genes? B) Plot the genes on a map c) If the genes were unlinked and the F1 females were mated with the F1 males, what would be the offspring in the F2 generation?

1st cross:

Parental) grogro ro+ro+ x gro+gro+ roro

F1) gro+gro ro+ro

2nd cross:

Parental) gro+gro ro+ro x grogro roro

Gametes) gro+ro+ gro ro

gro+ro gro ro

gro ro+ gro ro

gro ro gro ro

Punnet square)

gro+ro+ gro+ro gro ro+ gro ro

gro ro gro+gro ro+ro gro+gro roro grogro ro+ro grogro roro

F2)

0.518 grogro ro+ro (518 individuals)

0.471 gro+gro roro (471 individuals)

0.006 grogro roro (6 individuals)

0.005 gro+gro ro+ro (5 individuals)

Total number of individuals 1000

Note: These frequencies were calculated dividing the number of individuals belonging to each genotype by the total number of individuals in the F2.

To know if two genes are linked, we must observe the progeny distribution. If individuals, whos genes assort independently, are test crossed, they produce a progeny with equal phenotypic frequencies 1:1:1:1. If we observe a different distribution, that is that phenotypes appear in different proportions, we can assume that genes are linked in the double heterozygote parent.

In the exposed example we might verify which are the recombinant gametes produced by the F1 di-hybrid, and we can recognize them by looking at the phenotypes with lower frequencies in the progeny.

By performing this cross we know that the phenotypes with lower frequencies in the progeny are groucho, rough and wild-type. So the recombinant gametes are gro+ro+ and gro ro, while the parental gametes are gro+ro and gro ro+.

So, the genotype, in linked gene format, of the double heterozygote individual in the F1 is gro+ro/gro ro+.

To calculate the recombination frequency we will make use of the next formula: P = Recombinant number / Total of individuals. The genetic distance will result from multiplying that frequency by 100 and expressing it in map units (MU). One centiMorgan (cM) equals one map unit (MU).

The map unit is the distance between the pair of genes for which one of every 100 meiotic products results in a recombinant product.

The recombination frequency is:

P = Recombinant number / Total of individuals

P = 6 + 5 / 1000

P = 11 / 1000

P = 0.011

The genetic distance between genes, is 0.011 x 100= 1.1 MU.

Genetic Linkage Map:

Parental Phenotypes)

-----gro+------ro---- -----gro------ro+----

----- gro ------ro---- ---- gro------ ro ----

Recombinant phenotypes)

-----gro+------ro+---- -----gro------ro----

----- gro ------ ro---- -----gro------ro----

If the genes were unlinked and the F1 females were mated with the F1 males, the offspring in the F2 generation would have been

4/16 = 1/4 gro+gro ro+ro

4/16 = 1/4 gro+gro roro

4/16 = 1/4 grogro ro+ro

4/16 = 1/4 grogro roro

Their phenotypic frequencies would be 1:1:1:1 related.

7 0

3 years ago

Think Critically. Compare and contrast point source pollution and nonpoint source pollution.

Helga [31]

Answer:

Point-source pollution is easy to identify. As the name suggests, it comes from a single place. Nonpoint-source pollution is harder to identify and harder to address. It is pollution that comes from many places, all at once.

9 0

3 years ago