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Citrus2011 [14]

2 years ago

8

The equation of the circle whose center is at (3, 7) and whose radius is 6 is

1 answer:

muminat2 years ago

6 0

Answer:

$\large\boxed{(x-3)^2+(y-7)^2=36}$

Step-by-step explanation:

The equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have

(3, 7) - center

r = 6 - radius

Substitute:

$(x-3)^2+(y-7)^2=6^2\\\\(x-3)^2+(y-7)^2=36$

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HURRYYYYYYYYY!! What is the equation of the quadratic function with a vertex at (2, 25) and an x-intercept at (7,0)?

tangare [24]

Answer:

$y=-(x-7)(x+3)$

which is none of the choices provided.

Are you sure the question is right or even the choices?

You can even write it as:

$y=-(x+3)(x-7)$ but this is still not a choice.

Step-by-step explanation:

The vertex form of a quadratic is $y=a(x-h)^2+k$ .

This is called vertex form because it gives you the vertex is $(h,k)$ .

We are given that $(h,k)=(2,25)$ which makes our equation:

$y=a(x-2)^2+25$ .

We can find the value of $a$ by plugging in the x-intercept (7,0) for $(x,y)$ into:

$y=a(x-2)^2+25$

$0=a(7-2)^2+25$

$0=a(5)^2+25$

Subtract 25 on both sides:

$-25=a(5)^2$

$-25=a(25)$

Divide both sides by 25:

$\frac{-25}{25}=a$

$-1=a$ .

So the equation for the quadratic is:

$y=-1(x-2)^2+25$

Let's put this into factored form since all the choices are in factored form.

This will require us to multiply the (x-2)(x-2) out:

$y=-1(x-2)(x-2)+25$

$y=-1(x^2-2x-2x+4)+25$

$y=-1(x^2-4x+4)+25$

$y=-x^2+4x-4+25$

$y=-x^2+4x+21$

Factor out -1:

$y=-(x^2-4x-21)$

WE need to find two numbers that multiply to be -21 and add to be -4:

$y=-(x-7)(x+3)$

8 0

3 years ago

Read 2 more answers

Explain why x squared -8x+20 is always positive

Tpy6a [65]

Answer:

to square a number you multiply the number by itself.

a positive number times a positive number is a positive number.

a negative number times a negative number is a negative number.

and if you are multiplying 2 numbers with the same sign they will always be a positive number.

3 0

2 years ago

In the United States, among a representative group of 6,006 white men and 1,126 black men, ages 70-79 at diagnosis with stage IV

Ivenika [448]

Answer:

White men diagnosed with stage IV prostatic adenocarcinoma within the age bracket of 70-79 are 1.27 times more likely to survive five years after the diagnosis of stage IV prostatic adenocarcinoma than black men.

Step-by-step explanation:

The exposure is race and the outcome is survival.

Race Alive Dead T

W 2337 3669 6006

B 344 782 1126

Relative Risk - 1.27

White men diagnosed with stage IV prostatic adenocarcinoma within the age bracket of 70-79 are 1.27 times more likely to survive five years after the diagnosis of stage IV prostatic adenocarcinoma than black men.

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2 years ago

Solving quadratics

jeka57 [31]

The answer to this equation is 3

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3 years ago

Haylee can run 16 laps in 8 minutes. If she continues at this rate, how many minutes will it take her to run 30 laps?

KonstantinChe [14]

Step-by-step explanation:

1minute=2lap

30lap=30/2

=15minutes

4 0

2 years ago