Question

The equation of the circle whose center is at (3, 7) and whose radius is 6 is

Answer 1

Answer:

$\large\boxed{(x-3)^2+(y-7)^2=36}$

Step-by-step explanation:

The equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have

(3, 7) - center

r = 6 - radius

Substitute:

$(x-3)^2+(y-7)^2=6^2\\\\(x-3)^2+(y-7)^2=36$