The equation of a line parallel to y = 5x + 4 that passes through (-1 , 2) is y = 5x + 7
Step-by-step explanation:
The parallel lines have:
- Same slopes
- Different y-intercepts
The form of the linear equation is y = mx + b, where m is the slope of the line and b is the y-intercept
∵ The equation of the given line is y = 5x + 4
∴ m = 5 and b = 4
∵ The two lines are parallel
∴ Their slopes are equal
∴ The slope of the parallel line = 5
- Substitute the value of the slope in the form of the equation
∴ y = 5x + b
- To find b substitute x and y in the equation by the coordinates
of any point on the line
∵ The parallel line passes through point (-1 , 2)
∴ x = -1 and y = 2
∵ 2 = 5(-1) + b
∴ 2 = -5 + b
- Add 5 to both sides
∴ 7 = b
- Substitute the value of b in the equation
∴ y = 5x + 7
The equation of a line parallel to y = 5x + 4 that passes through (-1 , 2) is y = 5x + 7
Learn more:
You can learn more about the equations of the parallel lines in brainly.com/question/9527422
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<span>5ab^2 + 10ab
5ab^2 = 5ab *(b)
10ab = 5ab *(2)
so GCF of </span>5ab^2 + 10ab = 5ab
0
The answer is C
Ik this bc
Someone told me
Answer:
10 + x
Step-by-step explanation:
Sum means add
Hope this helps you :)
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Answer:
3.
Step-by-step explanation:
Implicit differentiation:
x^2 y + (xy)^3 + 3x = 0
x^2 y + x^3y^3 + 3x = 0
Using the product rule:
2x* y + x^2*dy/dx + 3x^2 y^3 + x^3* (d(y^3)/dx) + 3 = 0
2xy + x^2 dy/dx + 3x^2 y^3 + x^3* 3y^2 dy/dx + 3 = 0
dy/dx(x^2 + 3y^2x^3) = (-2xy - 3x^2y^3 - 3)
dy/dx= (-2xy - 3x^2y^3 - 3) / (x^2 + 3y^2x^3)
At the point (-1, 3).
the derivative = (6 - 81 - 3)/(1 -27)
= -78/-26
= 3.
