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Readme [11.4K]
3 years ago
10

Please help me in this question.Tell me if it is good. And if it is not good then do it for me please.

Mathematics
1 answer:
Orlov [11]3 years ago
6 0

Answer:

Y = 170, Z = 64.

Step-by-step explanation:

Since y is the external angle to x, which you got right, it is in fact, 180-10, = 170 degrees. And since z is the external to our unknown angle, that means it is equal to the sum of the other two angles in the triangle. That means z is 54 + 10, which is 64.

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Helpp with this for me pls due tomarrow
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22/5- 4 and 2/5

Step-by-step explanation:

8 0
3 years ago
Ronald invested $68160 for 8 years and earned 6.2% interest compounded annually
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Answer:

He earned 110287.3536 dollars

6 0
2 years ago
28 + 2A = 5A + 7<br><br> Please explain thank you!
Vinvika [58]
First you need to get x on one side of the equation and to do that subtract 2a from both sides.
28 + 2a = 5a + 7
-2a -2a
28=3a+7

Then we need to get a alone by subtracting 7 on both sides.
28=3a+7
-7 -7
21=3a

Finally divide each side by 3 and you should get a = 7. Hope this helps!
3 0
3 years ago
Inequality to x2 &lt; 64
Anarel [89]
              NOT MY WORDS TAKEN FROM A SOURCE!

(x^2) <64  => (x^2) -64 < 64-64 => (x^2) - 64 < 0 64= 8^2    so    (x^2) - (8^2) < 0  To solve the inequality we first find the roots (values of x that make (x^2) - (8^2) = 0 ) Note that if we can express (x^2) - (y^2) as (x-y)* (x+y)  You can work backwards and verify this is true. so let's set (x^2) - (8^2)  equal to zero to find the roots: (x^2) - (8^2) = 0   => (x-8)*(x+8) = 0       if x-8 = 0 => x=8      and if x+8 = 0 => x=-8 So x= +/-8 are the roots of x^2) - (8^2)Now you need to pick any x values less than -8 (the smaller root) , one x value between -8 and +8 (the two roots), and one x value greater than 8 (the greater root) and see if the sign is positive or negative. 1) Let's pick -10 (which is smaller than -8). If x=-10, then (x^2) - (8^2) = 100-64 = 36>0  so it is positive
2) Let's pick 0 (which is greater than -8, larger than 8). If x=0, then (x^2) - (8^2) = 0-64 = -64 <0  so it is negative3) Let's pick +10 (which is greater than 10). If x=-10, then (x^2) - (8^2) = 100-64 = 36>0  so it is positive Since we are interested in (x^2) - 64 < 0, then x should be between -8 and positive 8. So  -8<x<8 Note: If you choose any number outside this range for x, and square it it will be greater than 64 and so it is not valid.

Hope this helped!

:)
7 0
2 years ago
Use inverse operation to solve the question <br><br> 2/3z = -4<br><br><br> Z= ?
sweet [91]

Answer:

z=(-6)

Step-by-step explanation:

(2/3)*z=(-4)

2*z=3*(-4) --> We move the 3 from the left to the right part of the equation. It was dividing, so we move it multiplying.

2*z=(-12)

z=(-12)/2 --> It's the inverse case of before. 2 was multiplying, so we move it to the right by dividing it.

z=(-6)

7 0
2 years ago
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