Answer:
The maximum height of the ball is 256m
Step-by-step explanation:
Given the equation of a pathway modelled as pathway can be modeled by h = -16t² + 128t
At maximum height, the velocity of the ball is zero.
velocity = dh/dt
velocity = -32t + 128
Since v = 0 at maximum height
0 = -32t+128
32t = 128
t = 128/32
t = 4seconds
The maximum height can be gotten by substituting t = 4 into the modelled equation.
h = -16t² + 128t
h = -16(4)²+128(4)
h = -16(16)+512
h = -256+512
h = 256m
4x + 8 = 2x + 7 + 2x - 20
4x + 8 = 4x - 13
8 = -13
no solution.
hope that helps, God bless!
Answer:

Step-by-step explanation:
the information we have is:
- the radius of the circle in the base:
(u for units)
- and the height of the cone:

to find the volume we need the formula for the volume of a cone:

where r is the radius and h is the height.
Substituting the known values to find the volume:

the volume in terms of
is 
and if we substitute the value of pi:
we get:
