Question

(π/6)*[√4] + (3!)^2 - (46,656)^(1/3) i dont know this it is confusing HELP!

Answer 1

The answer is one
the reason is because
(π/6)*[√4] + (3!)^2 - (46,656)^(1/3) is one

Answer 2

Special things are confusing

so

some basica rules
$x^ \frac{m}{n}= \sqrt[n]{x^m}$
and pemdas


so
parentahsees first
3!=3*2*1=6
now we have
(π/6)*[√4] + (6)^2 - (46,656)^(1/3)
exponents
6^2=36
(46,656)^(1/3)=∛46656=36

now we have
(π/6)*[√4] + 36-36
multiply
(π/6)*[√4]=$\frac{pi \sqrt{4} }{6} = \frac{2pi}{6}= \frac{pi}{3}$

now we have
$\frac{pi}{3}$+36-36
$\frac{pi}{3}$+0
$\frac{pi}{3}$

the simplified expression is $\frac{pi}{3}$