Ask question

Ask question

All categories

3 years ago

15

Movie genres. The pie chart summarizes the genres of 120 first-run movies released in 2005. a) Is this an appropriate display fo

r the genres

1 answer:

butalik [34]3 years ago

5 0

Answer:

Yes, it is appropriate

Step-by-step explanation:

Given

See attachment for pie chart

Required

Is the pie chart appropriate

The attached pie chart displays the distribution of each of the 4 genre. The partition occupied represents the measure of each genre.

You might be interested in

16. Which is greater, 4^-2 or<br> 2^-4? How do you know?<br> Those are exponents.

gladu [14]

Answer:

Both are equal to $\frac{1}{16}$

Step-by-step explanation:

If the exponent is negative we can turn it into a fraction and make it positive.

This means the number goes to the denominator and the numerator becomes one. Therefore the following.

$4^{-2} = \frac{1}{4^{2} } =\frac{1}{16}$

$2^{-4} =\frac{1}{2^{4} } = \frac{1}{16}$

4 0

3 years ago

Triangle CAT is transformed to produce triangle DOG.

PilotLPTM [1.2K]

Using transformations and congruency concepts, it is found that with these following transformations, the triangles will be congruent.

A reflection, then a translation.
A rotation, then a reflection.

--------------------------

Two triangles are congruent if they have the <u>same lengths</u> of the sides and the <u>same angles.</u>

In a reflection, there is a rule that changes the <u>coordinates (x,y)</u>, but does <u>not </u>change <u>the lengths</u> of the sides of the triangles, thus they will still be congruent.
A <u>reflection is also a special case of rotation</u>, thus, in a rotation, the triangles are also congruent.
A translation is also similar to a reflection, using rules to shift the triangle up, down, left or right according to it's coordinates, not changing the sides or angles, thus congruent.
In a dilation, the <u>lengths of the sides are changed</u>, thus, the triangles will not be congruent.

--------------------------

Thus, from the bullet points above, the correct options are:

A reflection, then a translation.
A rotation, then a reflection.

A similar problem is given at brainly.com/question/24267298

3 0

2 years ago

What is the equation of a line, in point-slope form, that passes through (−2, −6) and has a slope of 1/3?

Alexus [3.1K]

The equation of a line in point-slope form is y-6=1/3(x-2) remember point-slope is y1-y2=m(x1-x2)

8 0

2 years ago

Can someone help me?! I don’t understand how to do these problems

Dmitriy789 [7]

Answer:

first do 9x40 and get your answer then do 18x3 and get that answer and then add to do answers together

7 0

3 years ago

Read 2 more answers

A student solves the following equation and

Phoenix [80]

Answer:

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

Step-by-step explanation:

Considering the expression

$\frac{3}{a+2}-6\cdot \frac{a}{-4+a^2}=\frac{1}{a-2}$

$\frac{3}{a+2}-\frac{6a}{-4+a^2}=\frac{1}{a-2}$

$\mathrm{Find\:Least\:Common\:Multiplier\:of\:}a+2,\:-4+a^2,\:a-2:\quad \left(a+2\right)\left(a-2\right)$

$\mathrm{Multiply\:by\:LCM=}\left(a+2\right)\left(a-2\right)$

$\frac{3}{a+2}\left(a+2\right)\left(a-2\right)-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right)=\frac{1}{a-2}\left(a+2\right)\left(a-2\right)$

as

$\frac{3}{a+2}\left(a+2\right)\left(a-2\right):\quad 3\left(a-2\right)$

$-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right):\quad -6a$

$\frac{1}{a-2}\left(a+2\right)\left(a-2\right):\quad a+2$

so equation becomes

$3\left(a-2\right)-6a=a+2$

$-3a-6=a+2$

$-3a-6+6=a+2+6$

$-4a=8$

$\mathrm{Divide\:both\:sides\:by\:}-4$

$\frac{-4a}{-4}=\frac{8}{-4}$

$a=-2$

$\mathrm{Verify\:Solutions}$

$\mathrm{Take\:the\:denominator\left(s\right)\:of\:}\frac{3}{a+2}-6\frac{a}{-4+a^2}-\frac{1}{a-2}\mathrm{\:and\:compare\:to\:zero}$

$\mathrm{Solve\:}\:a+2=0:\quad a=-2$

$\mathrm{Solve\:}\:-4+a^2=0:\quad a=2,\:a=-2$

$\mathrm{Solve\:}\:a-2=0:\quad a=2$

So the following points are undefined

$a=-2,\:a=2$

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

4 0

3 years ago